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Answer 1I am a layman so this answer will be basic, until some kind of expert [Physicist, Engineer, Pole Lineman] can improve it.

The amount of sag is relative to the tension in the suspended cable.

The tension in a cable is naturally distributed evenly along the entire length of the cable, by virtue of the sag. I'm not positive, but I think that the naturarlly occurring shape of the curve is described as a "catenary" curve.

The less the "droop," indicates a greater tension, and the sag versus tension ratio IS NOT LINEAR, meaning that to get ever more sag pulled out of a cable, takes tremendouly increasing higher tension.

The amount of tension required to pull a heavy cable perfectly straight, or horizontal. is ASTRONOMICALLY HIGH, which almost always exceeds the tensile strength of the cable itself.

This means that if one were to try to pull all the sag out of a suspended cable, at some point, the cable would break. So, as a result, a certain amount of sag is left in a suspended cable.

When I was in the Army, the Signal Corps Pole Linemen, had charts which they eventually learned by heart, which indicated, for any given line size/weight per foot, the proper amount of sag to leave in the cable in order to not exceed the safe tension.

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Q: When telegraph wires are hung sufficient sag is left Why is this so?
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