When a gun is fired, the projectile goes one way, the gun goes in the opposite direction. That is recoil. Recoil velocity would be the speed at which the gun moves when it recoils. Since the gun is heavier than the projectile, it will recoil more slowly than the projectile moves.
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
.351 km/hr
The law that says every action has an equal and oppsite reaction: the momentum of the bullet is balanced by the equal momentum of the gun (and shooter) in the opposite direction - the recoil.
Well, remember that, for every action, there is an equal and opposite reaction. In an automatic firearm, this will be enhanced by the action, which exerts force against the bolt carrier or slide to cycle it.
Bullet forward, gun back - as in when the gun is fired, the bullet goes forward, and the explosion pushes (recoil) the gun backwards.
When a gun is fired, the projectile goes one way, the gun goes in the opposite direction. That is recoil. Recoil velocity would be the speed at which the gun moves when it recoils. Since the gun is heavier than the projectile, it will recoil more slowly than the projectile moves.
the recoil of a bullet fired from a gun
The recoil of a bullet being fired from a gun is a good example, the action force is the gun pushing the bullet away from the gun and the reaction force is the bullet pushing back against the gun (recoil).
When a gun is fired a bullet (or cartridge) with a small mass but a very high velocity is ejected. The recoil of the gun is a reaction to this force and is sufficient to push back the person who fired the weapon.
Yup, Newton's 3rd Law: Action:Reaction
I think you're mistaking "revoke" for "recoil". In the case of firearms, recoil is the word that describes the rebounding force that the shooter feels after firing a gun. A cartridge is an unfired bullet plus a small amount of explosive material (ie: gunpowder) which are held together by an outer casing. When a gun is fired, a metal part called the hammer strikes the back end of the cartridge that is loaded in the chamber, igniting the gunpowder and creating a contained explosion inside the gun. The bullet seperates from its casing and is forced down and out of the barrel of the gun by the explosion, and the recoil the shooter feels is the force of the explosion, which is trapped inside the gun and escapes by pushing the bullet out of the only opening it can fit through. The force pushing the bullet and explosion out of the gun also pushes back in the opposite direction towards the shooter (aka: recoil). There is always recoil when a gun is fired, but experienced shooters can predict the force of recoil and brace themselves against it, keeping the gun steady in their hands. The larger the amount of gunpowder, the bigger the explosion and recoil caused by it.
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
The barrel is usually above the centerline of the gun. When fired, recoil pushes straight back from the line of the barrel, but that is offset above the centerline, and causes the gun to pivot.
It's the recoil from the force of the bullet being fired. The gun powder pushes the bullet forward and also equally pushes the gun back into your hand.
.351 km/hr
Yes, but they will fire as a single shot. Unless the pistol is modified, it will not cycle when fired. These guns are recoil operated- and blanks do not produce significant recoil.