number of turns......... If turns is more than more impedance..
The term, 'percentage impedance', is a little misleading, as it is defined as 'the value of primary voltage that will cause rated current to flow in the secondary winding, expressed as a percentage of the rated primary voltage'. So, the test is carried out as follows: the secondary winding is short-circuited through an ammeter capable of reading the rated secondary current. A variable voltage is applied to the primary winding. The primary voltage is gradually increased until the ammeter indicates rated secondary current. That primary voltage is then expressed as a percentage of the rated primary voltage -and that value is the transformer's 'percentage impedance'.
Inherently, the actual impedance seen at the secondary voltage will be different than that seen at the primary voltage. To make things easy, we use symmetrical components, where transformers are reduced to a p.u. (per unit) impedance. 100 x p.u. is equivalent to the percentage impedance you are referring to. When converted to per unit, a transformer has one impedance, not two, so it does not matter whether you are looking through the transformer from the secondary or the primary.
Impedance (Z) voltage is the amount of voltage applied to the primary side to produce full load current in the secondary side. It is usually listed on the transformer nameplate, expressed as a percent, and measured by conducting a short circuit test.
% voltage drop on full load from the secondary to the primary due to leakage reactance and the resistance of the windings.Answer'Percentage impedance' is a confusing term. It describes the value of primary voltage that will cause the rated secondary current to flow in the short-circuited secondary winding, expressed as a percentage of the rated primary voltage.
Voltage on primary/Primary turns = Voltage on secondary/Secondary turns
The current in the secondary when the voltage is twice the primary will be one half of the primary. The current in the primary when the voltage is twice the secondary will be twice the secondary.
When the primary and secondary voltages are the same the transformer is being used for isolation. The secondary side will have galvanic isolation from the primary side. The purpose of the is to protect secondary load if a fault occurs on the primary side. The impedance of the transformer will limit the fault current on the secondary which should save equipment.
The secondary winding leakage inductance limits the current during a short. It seems that the current through the primary is limited by winding resistance and leakage resistance when the secondary is shorted.
Power transformers have an impedance (Z) rating that is listed in %. So the nameplate might state 5% Z for example. What this means is that when the secondary conductors are bolted together then 5% of the rated primary voltage is applied and will generate 100% current in flow in the secondary. Example: you have a 75KVA Delta-Wye 5% Z transformer with a 480V primary rating and 208/12 secondary rating. The amp rating of the secondary is 208A [75,000/(1.732x208)] So if you applied 24VAC to the primary with the secondary bolted together with busbar then you would have 208A of current flow.
I assume the primary has 12 volts applied. The voltage ratio from primary / secondary is equivalent to the turns ratio = 10/20, so the primary voltage is 1/2 of the secondary voltage. The secondary voltage is 24.
Your question reveals a misunderstanding of how a transformer works.The primary current of a transformer is determined by the secondary current, not the other way around. When the secondary voltage is applied to a load, a secondary current flows, and its value is determined by the secondary voltage and the load impedance. This secondary current then determines the value of the primary current.
If the primary is 1 and the secondary 200 then multiply the primary voltage by 200.