No it will not run
240V. 415 / 1.73 = 240
To answer your question properly, you need to know the input power to these machines, whereas you are specifying their output powers. In other words, you really need to know their efficiencies in order to determine their input powers.Once you have figured out their input powers, then you need to divide the power by the supply voltage in the case of the single-phase motor, and the power divided by 1.732 times the supply voltage in the case of the three-phase motor.Incidentally, your motors' specs should either be 230/400 V or 240/415 V, NOT 230/415 V.
Yes, just use L1 and L2 ( just 2 of the 3 legs), or one of the legs to a neutral wire if equipped. Just make sure the voltage is the same as the 220 volts you wish to have with single phase service.
If the generator is 3-phase 120/208 v. it produces 104.21amps per phase using the formula 30,000 / (1.73 x 208 x .80). If it is 277/480 v. It gives 45.18 amps. A singlephase generator will give 125 amps at 240 volts and 62.5 amps at 480v.
The only relevant number is the kw. Then you just divide by the power factor to get the KVA. 0.8 is a pretty typical PF, so that would give you a KVA of about 9.4. But motors can take up to 5 times their rated current on start-up, so you need to make sure you have a generator that will handle that instantaneous current.
240V. 415 / 1.73 = 240
415 volts
415*800*pf
415/240 V, 50 Hz
1/3 rd lost
415 V is the 'line voltage', and 240 V is the 'phase voltage' of a 415/240-V three-phase, four-wire, system. These were the standard nominal voltages used in the UK before EU 'harmonisation' forced them to be 'renamed' (but not actually changed) to '400/230 V'!! So there really isn't such a thing as separate '415-V' and '240-V' three-phase systems. And there is no economic way of changing the supply frequency to a different frequency. Incidentally, the symbol for 'hertz' is 'Hz', not 'htz'.
10000 = 415 * i i = 10000/415 = 24 a <<>> The formula you are looking for when KVA is known is I = KVA x 1000/1.73 x E = 10000/1.73 x 415 = 10000/240 = 41.6 amps.
To answer your question properly, you need to know the input power to these machines, whereas you are specifying their output powers. In other words, you really need to know their efficiencies in order to determine their input powers.Once you have figured out their input powers, then you need to divide the power by the supply voltage in the case of the single-phase motor, and the power divided by 1.732 times the supply voltage in the case of the three-phase motor.Incidentally, your motors' specs should either be 230/400 V or 240/415 V, NOT 230/415 V.
Answer for UK, Europe and countries running a 50 Hz supply service.A farm that takes a 700-amp supply on 3-phase 415 volts is a big farm drawing 500 kVA so it really needs a 750 kVA generator that would be expected to use 60-70 gallons of diesel per hour. It should be noted that 3 phase 415 volts is a 50 Hertz generated supply.At lower voltages the power drawn would be less, but the answer is independent of the supply frequency.Answer for countries running a 60 Hz supply service.A farm that takes a 700-amp supply on 3-phase 208 volts is a farm drawing 250 kVA that needs a 300-350 kVA generator. It would be expected to use 30-40 gallons of diesel per hour.
Yes, just use L1 and L2 ( just 2 of the 3 legs), or one of the legs to a neutral wire if equipped. Just make sure the voltage is the same as the 220 volts you wish to have with single phase service.
The voltage in a three phase delta system is stated by the phase to phase voltage. If it is a wye connection the phase to neutral is represented by the two voltages. e.g. 120/208, 240/415, 277/480, 347/600, 7225/12500, etc.
If the generator is 3-phase 120/208 v. it produces 104.21amps per phase using the formula 30,000 / (1.73 x 208 x .80). If it is 277/480 v. It gives 45.18 amps. A singlephase generator will give 125 amps at 240 volts and 62.5 amps at 480v.