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cross polarization = xpd so, xpd = 20 log E11/E12 where E11 and E12 are the two waves.

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cross polarization = xpd so, xpd = 20 log E11/E12 where E11 and E12 are the two waves.

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10% tolerance.

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Yes It Is.

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It is 2.3476*10^12, almost the same as in the question!

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/* Bubble sort:

code snippet only

nos to be sorted are in the array named 'n' of size 'N'

for(int i=0;i<N-1;i++)

for(int j=i+1;j<N-1-i;j++)

if(n[j]>n[j+1])

swap(n[j],n[j+1]);

*/

/*

insertion sort

int v,j;

for(int i=1;i<N;i++)

{

v=n[j];

for(int j=i-1;j>0&&n[j]>v;j--)

n[j+1]=n[j];

n[j+1]=v;

}

*/

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