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3c - 12 = 14 + 5c

Subtract 3c from each side:

-12 = 14 + 2c

Subtract 14 from each side:

-26 = 2c

Divide each side by 2:

-13 = c

This answer is:
Related answers

3c - 12 = 14 + 5c

Subtract 3c from each side:

-12 = 14 + 2c

Subtract 14 from each side:

-26 = 2c

Divide each side by 2:

-13 = c

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letter B

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3c+6=18

3c+6-6=18-6

3c=12

3c÷3=12÷3

c=4

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(3c +15)/(c2 - 5) + c/(c + 5)

= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)

= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)

= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)

= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)

= (c2 - 2c + 15)/(c - 5)(c + 5)

= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)

= (c + 3)/(c + 5)

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3c-7 = -4

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