The Nyquist frequency for a signal with a maximum bandwidth of 1 KHz is 500 Hz, however that will lead to aliasing unless perfect filters are available.

The Nyquist rate for a signal with a maximum bandwidth of 1 KHz is 2 KHz, so the answer to the question is 2 KHz, or 500 microseconds.

The answer depends on the accuracy desired.

a. The minimum bandwidth, a rough approximation, is B = bit rate /2, or 500 kHz. We need

a low-pass channel with frequencies between 0 and 500 kHz.

b. A better result can be achieved by using the first and the third harmonics with the required

bandwidth B = 3 × 500 kHz = 1.5 MHz.

c. A still better result can be achieved by using the first, third, and fifth harmonics with

B = 5 × 500 kHz = 2.5 MHz

1 KHz.

Period = 1 / (frequency) = 1 / 500 = 0.002 second = 2 milliseconds

Period = reciprocal of frequency = 1 / (500) = 0.002 second