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If you mean:

Lim(x→2) 3x + 1

Then the answer is 7

If you mean something else, then you'll need to clarify your question.

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to chua mei kei i love you ahhahaha

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tan x = sin x / cos x, so:

lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).

tan x = sin x / cos x, so:

lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).

tan x = sin x / cos x, so:

lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).

tan x = sin x / cos x, so:

lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).

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size_t trim (char *p)

{

char *from, *lim, *to;

from= p;

lim= p + strlen (p);

to= p;

while (lim>from && lim[-1]==' ') --lim;

while (from<lim && from[0]==' ') ++ from;

while (from<lim) *to++ = *from++;

*to= '\0';

return to-p;

}

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