absolute magnitude: Definition from Answers.com

This article is about the brightness of stars. For the science fiction magazine, see Absolute Magnitude (magazine).

In astronomy, absolute magnitude (also known as absolute visual magnitude when measured in the standard V phometric band) measures a celestial object's intrinsic brightness. To derive absolute magnitude from the observed apparent magnitude of a celestial object its value is corrected from distance to its observer. Absolute magnitude then equals the apparent magnitude an object would have if it were at a standard luminosity distance (10 parsecs, 1 AU, depending on object type) away from the observer, in the absence of astronomical extinction. It allows the true brightnesses of objects to be compared without regard to distance. Bolometric magnitude is luminosity expressed in magnitude units; it takes into account energy radiated at all wavelengths, whether observed or not.

The absolute magnitude uses the same convention as the visual magnitude, with a factor of 100^(0.2) (≈2.512) difference in brightness between steps in magnitude. The Milky Way, for example, has an absolute magnitude of about −20.5. So a quasar at an absolute magnitude of −25.5 is 100 times brighter than our galaxy (because (100^(0.2))^{(-20.5-(-25.5))} = (100^(0.2))⁵ = 100). If this particular quasar and our galaxy could be seen side by side at the same distance, the quasar would be 5 magnitudes (or 100 times) brighter than our galaxy.

1 Stars and galaxies (M)
2 Solar System bodies (H)
- 2.1 Apparent magnitude
  - 2.1.1 Example
3 Meteors
4 See also
5 Notes
6 External links

Stars and galaxies (M)

In stellar and galactic astronomy, the standard distance is 10 parsecs (about 32.616 light years, or 3 × 10¹⁴ kilometres). A star at ten pc has a parallax of 0.1" (100 milli arc seconds). For galaxies (which are of course themselves much larger than 10 pc, and whose brightness cannot be sensibly observed from so short a distance) the definition is referred to the apparent brightness of a point-like or star-like source of the same total luminosity as the galaxy, as it would look if observed at the standard 10 pc distance.

In defining absolute magnitude it is necessary to specify the type of electromagnetic radiation being measured. When referring to total energy output, the proper term is bolometric magnitude. The bolometric magnitude can be computed from the visual magnitude plus a bolometric correction, $M b o l = M V + B C$ . This correction is needed because very hot stars radiate mostly ultraviolet radiation, while very cool stars radiate mostly infrared radiation (see Planck's law). The dimmer an object (at a distance of 10 parsecs) would appear, the higher its absolute magnitude. The lower an object's absolute magnitude, the higher its luminosity. A mathematical equation relates apparent magnitude with absolute magnitude, via parallax.

Many stars visible to the naked eye have an absolute magnitude which would be capable of casting shadows if they were to lie at 10 parsecs from the Earth: Rigel (−7.0), Deneb (−7.2), Naos (−6.0), and Betelgeuse (−5.6). For comparison, Sirius has an absolute magnitude of 1.4 which is greater than the Sun's absolute visual magnitude of 4.83 (it actually serves as a reference point). The Sun's absolute bolometric magnitude is 4.75.^{[clarification needed]}

Absolute magnitudes for stars generally range from −10 to +17. The absolute magnitude for galaxies can be much lower (brighter). For example, the giant elliptical galaxy M87 has an absolute magnitude of −22.

Computation

One can compute the absolute magnitude $M\!\,$ of an object given its apparent magnitude $m\!\,$ and luminosity distance $D_L\!\,$ :

$M = m - 5 ((\log_{10}{D_L}) - 1)\!\,$

where $D_L\!\,$ is the star's luminosity distance in parsecs, wherein 1 parsec is approximately 3.2616 light-years.

For nearby astronomical objects (such as stars in our galaxy) the luminosity distance D_L is almost identical to the real distance to the object, because spacetime within our galaxy is almost Euclidean. For much more distant objects the Euclidean approximation is not valid, and General Relativity must be taken into account when calculating the luminosity distance of an object.

In the Euclidean approximation for nearby objects, the absolute magnitude $M\!\,$ of a star can be calculated from its apparent magnitude and parallax:

$M = m + 5 (\log_{10}{p} + 1)\!\,$

where p is the star's parallax in arcseconds.

You can also compute the absolute magnitude $M\!\,$ of an object given its apparent magnitude $m\!\,$ and distance modulus $\mu\!\,$ :

$M = m - {\mu}\!\,$

Examples

Rigel has a visual magnitude of $m V = 0.18$ and distance about 773 light-years

$M_V = 0.18 - 5 \cdot (\log_{10} \frac{773}{3.2616} - 1) = -6.7$

Vega has a parallax of 0.129", and an apparent magnitude of +0.03

$M_V = 0.03 + 5 \cdot (1 +\log_{10}{0.129}) = +0.6$

Alpha Centauri A has a parallax of 0.742" and an apparent magnitude of −0.01

$M_V = -0.01 + 5 \cdot (1 +\log_{10}{0.742}) = +4.3$

The Black Eye Galaxy has a visual magnitude of m_V=+9.36 and a distance modulus of 31.06.

M V = 9.36 - 31.06 = - 21.7

Apparent magnitude

(Main article: apparent magnitude)

Given the absolute magnitude $M\!\,$ , for objects within our galaxy you can also calculate the apparent magnitude $m\!\,$ from any distance $d\!\,$ :

$m = M + 5 (\log_{10}{d} - 1)\!\,$

For objects at very great distances (outside our galaxy) the luminosity distance D_L must be used instead of d.

Given the absolute magnitude $M\!\,$ , you can also compute apparent magnitude $m\!\,$ from its parallax $p\!\,$ :

$m = M - 5 (\log_{10}p + 1)\!\,$

Also calculating absolute magnitude $M\!\,$ from distance modulus $\mu\!\,$ :

$m = M + {\mu}\!\,$

Bolometric magnitude

Bolometric magnitude corresponds to luminosity, expressed in magnitude units; that is, after taking into account all electromagnetic wavelengths, including those unobserved due to instrumental pass-band, the Earth's atmospheric absorption, or extinction by interstellar dust. For stars, in the absence of extensive observations at many wavelengths, it usually must be computed assuming an effective temperature.

Solar System bodies (H)

For planets, comets and asteroids a different definition of absolute magnitude is used which is more meaningful for nonstellar objects.

In this case, the absolute magnitude is defined as the apparent magnitude that the object would have if it were one astronomical unit (au) from both the Sun and the observer and at a phase angle of zero degrees. This is physically impossible, as it requires the observer to be located at the centre of the Sun, but it is convenient for purposes of calculation.

To convert a stellar or galactic absolute magnitude into a planetary one, subtract 31.57.

Apparent magnitude

The absolute magnitude can be used to help calculate the apparent magnitude of a body under different conditions.

$m = H + 2.5 \log_{10}{(\frac{d_{BS}^2 d_{BO}^2}{p(\chi) d_0^4})}\!\,$

where

$d_0\!\,$ is 1 au, $\chi\!\,$ is the phase angle, the angle between the Sun-Body and Body-Observer lines; by the law of cosines, we have:

$\cos{\chi} = \frac{ d_{BO}^2 + d_{BS}^2 - d_{OS}^2 } {2 d_{BO} d_{BS}}\!\,$

$p(\chi)\!\,$ is the phase integral (integration of reflected light; a number in the 0 to 1 range)

Example: (An ideal diffuse reflecting sphere) - A reasonable first approximation for planetary bodies

$p(\chi) = \frac{2}{3} ( (1 - \frac{\chi}{\pi}) \cos{\chi} + (1/\pi) \sin{\chi} )\!\,$

A full-phase diffuse sphere reflects ⅔ as much light as a diffuse disc of the same diameter

Distances:

$d_{BO}\!\,$ is the distance between the observer and the body

$d_{BS}\!\,$ is the distance between the Sun and the body

$d_{OS}\!\,$ is the distance between the observer and the Sun

Example

Moon

$H_{Moon}\!\,$ = +0.25

$d_{OS}\!\,$ = $d_{BS}\!\,$ = 1 au

$d_{BO}\!\,$ = 384.5 Mm = 2.57 mau

How bright is the Moon from Earth?

Full Moon: $\chi\!\,$ = 0, ( $p(\chi)\!\,$ ≈ 2/3)

$m_{Moon} = 0.25 + 2.5 \log_{10}{(\frac{3}{2} 0.00257^2)} = -12.26\!\,$

(Actual -12.7) A full Moon reflects 30% more light at full phase than a perfect diffuse reflector predicts.

Quarter Moon: $\chi\!\,$ = 90°, $p(\chi) \approx \frac{2}{3\pi}\!\,$ (if diffuse reflector)

$m_{Moon} = 0.25 + 2.5 \log_{10}{(\frac{3\pi}{2} 0.00257^2)} = -11.02\!\,$

(Actual approximately -11.0) The diffuse reflector formula does better for smaller phases.

Meteors

For a meteor, the standard distance for measurement of magnitudes is at an altitude of 100 km (62 mi) at the observer's zenith.^[1]^[2]

Notes

^ "Absolute magnitude of meteors", Glossary, International Meteor Organization, http://www.imo.net/glossary#term66, retrieved 2008-07-16
^ "Absolute magnitude of Solar System bodies", Solar System Dynamics Glossary, NASA Jet Propulsion Laboratory, http://ssd.jpl.nasa.gov/?glossary&term=H, retrieved 2008-07-16

External links

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absolute magnitude

Contents

Stars and galaxies (M)

Computation

Examples

Apparent magnitude

Bolometric magnitude

Solar System bodies (H)

Apparent magnitude

Example

Meteors

See also

Notes

External links