Asked:
2 minutes ago

In:
Ancient Egypt

Asked:
2 minutes ago

Asked:
11 minutes ago

In:
Video Games

Asked:
31 minutes ago

More new questions »

Answered

Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.

Answered

In Technology

The easiest method today is by using a clamp meter. It "clamps" around a single conductor and measures the magnetic field (you can't get a reading by clamping around a regula…r appliance cord, as both conductors will cancel each other out). (MORE)

Answered

In Technology

Answer Hi, It really depends on when your home was built and whether or not you have an older home that had an upgrade at one time or another. For older home…s, it was usually 60 amps and for the newer homes, it's usually 100 amp service. Most homes today have 100 amp service, but lately, the trend has been installing a higher amperage service, usually around 200 amps. All that means, is that you have that much power available, and of course, you're generally billed for what you use and not how large the available service is. Hope that helps, Cubby (MORE)

Answered

In the UK the third rail is 750v DC 400amps the Overhead Live Electrical is 25000v AC

Answered

In Batteries

That will depend on a few things. The current output of the battery will depend on the operating voltage of the battery and the load resistance. If you know the load resistanc…e and operating voltage, you can calculate the current using Ohm's Law. The Ohm's Law equation is I=V/R where "I" represents current in Amps, "V" represents voltage in volts and "R" represents resistance in ohms. For a standard C battery, the operating voltage will start out at approximately 1.5 Volts but that voltage will decrease as charge is drained from the battery. The load resistance should remain constant so the current output of the battery will steadily decrease over time. You could use a multimeter to measure the voltage and load resistance across the terminals of the battery. See the related link for a Duracell C battery datasheet for more details on how a battery would operate under standard usage conditions. (MORE)

Answered

The formula for amperage is: I = V / R I = amperage, V = voltage, and R = resistance. Also amperage can be found by using the following formulas. I = P / V, Amps = Watts/Volt…s I = sq root P/R, Amps = the square root of (power divided by resistance) watts/ohms. (MORE)

Answered

By inventing something one creates something that wasn't and creates something that is. Amperage was always there, and various people characterized what was meant by current a…nd how it manifested itself under certain circumstances. For example, in a lightening strike there is a lot of current flowing through the air. Imagine Ben Franklin flying his kite in a storm. He was trying to see how one could harness the power of electricity. For more info research the following individuals: André Ampère (1775-1836) Alessandro Volta (1745-1827) Georg Simon Ohm (1787-1854) Ernest Rutherford (1871-1937) Benjamin Franklin (1706-1790) Thomas Alva Edison (1847-1931) Michael Faraday (1791-1867) Nicholas Tesla (1856 - 1943) (MORE)

Answered

In Uncategorized

The question should be, "How should electrical current measured?" Current is measured in Amperes using an Ammeter placed in series with the conductor of the current. This is i…mpractical, so most ammeters have windings of wire that pick up the field generated around the conductor in question. This winding, or coil, is very carefully sized and the meter very carefully calibrated to yield correct readings of current without a direct connection. (MORE)

Answered

Often CFLs are marked with the current. If not, find out the watts and the volts. Divide the watts by the volts to find the current, then double the current because the po…wer factor could be as low as 0.5 with CFLs. That will tell you a safe value to use for the current when planning the wiring. (MORE)

Answered

Lamp cord is #18 in size and is rated for 10 amps. This type of wire is strictly for use on lamps only and not to be used for power wiring.