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# What is the antiderivative of -cscxcotx?

First, antiderivative = a solution to the indefinite integral therefore to integrate -(csc(x))(cot(x)) first convert it to -cos(x)/sin 2 (x) To integrate â«-cos(x)/s…in 2 (x) dx, use substitution u = sin(x) and du/dx = cosx This will make it â«-1/u 2 du and the antiderivative is 1/u +c, therefore the answer is 1/sin(x) + c. (MORE)