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27

Explanation:

formulae: n(A^B)=n(A)+n(B)-n(AvB)

we have to findout n(B).

n(B)=n(A^B)+n(AvB)-n(A)

=10+50-30

=30

but here 3 members are not belongs to either of club members

so, =30-3

=27.

Now we got the result

This answer is:
Related answers

27

Explanation:

formulae: n(A^B)=n(A)+n(B)-n(AvB)

we have to findout n(B).

n(B)=n(A^B)+n(AvB)-n(A)

=10+50-30

=30

but here 3 members are not belongs to either of club members

so, =30-3

=27.

Now we got the result

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if (a > b && a > c) printf("%d\n", a);

else if (b > c) printf("%d\n", b);

else printf("%d\n", c);

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Uncle B <3 x

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a is 3m

b is 3n

m and n are relatively prime - they do not have any common factors.

a2 = 9m2

Since m had no factors in common with n, m2 also has no factors in common with n. We know that 3 is a common factor of a and b. The only new possible factor between a2 and b is the second 3 when a is squared. We do not know whether b had more than one factor of 3. So, the greatest common factor of a2 and b, when the greatest common factor of a and b is 3, is either 3 or 9.

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It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n

where nCr = n!/[r!*(n-r)!]

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