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Metal alkyls undergo beta-hydride elimination (the most facile decomposition pathway) which is not usually possible in metal aryls.

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Metal alkyls undergo beta-hydride elimination (the most facile decomposition pathway) which is not usually possible in metal aryls.

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The compound SnH2 would be called either tin(II) hydride or stannous(II) hydride, but I'm not sure such a compound exists. The more common hydride of tin is tin(IV) hydride which is H2Sn, or SnH2.

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sodium hydride

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Phosphorous Hydride = PH3

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