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c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24

This answer is:
Related answers
c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24



c + c + 1 = 49

2*c + 1 = 49

2*c = 48

c = 24

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If that's (c + 1) squared, (c + 1)(c + 1) = c^2 + 2c + 1

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If that's + c3, the answer is c(c - 1)(c + 1)(c + 1)

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1 degree, C. is colder than 7 degrees, C.

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use this strategy: integral of (b^x) dx = (b^x)/ln(b) + K [K is integration constant, b is not a variable]

rewrite (1/c)^(1-x) = ((1/c)^1)*((1/c)^(-x)) = (1/c)*(c^x). (1/c) is a constant, so bring outside the integral, then let b = c in the formula above, and you have (1/c)*(c^x)/ln(c) + K

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