| Dictionary: calculus of variations |
| 5min Related Video: calculus of variations |
| Sci-Tech Encyclopedia: Calculus of variations |
An extension of the part of differential calculus which deals with maxima and minima of functions of a single variable. The functions of the calculus of variations depend in an essential way upon infinitely many independent variables. Classically these functions are usually integrals whose integrand depends on a function whose specification by any finite number of parameters is impossible. For example, let C be a smooth bounded region of a space of m variables, x1, x2, …, xm, let y be any function of some smooth class on C and its boundary into real numbers or into n-tuples of real numbers and taking specified values on the boundary, and let f(x, y, p) be a smooth function of 2m + 1 variables x1, x2, …, xm, y, p1, p2, …, pm. Then the integral, shown below, is a function on
the space of functions y to the real numbers, and this space of functions is infinite dimensional unless excessive restrictions are placed on it. Here yx denotes the derivatives ∂y/∂x.
The calculus of variations studies such functions and their maxima and minima. The limitation of the competing functions is made realistically, and with sufficient restrictions it is possible to arrive at a rewarding theory; these restrictions do not always include the fixed boundary conditions stated above.
Principal applications may be to physical systems involving flexible components or time-dependent orbits; equilibrium positions or orbits may be determined by minimizing energy or action integrals. The problems are of mathematical interest because of intrinsic difficulties (largely related to lack of topological compactness of bounded regions in spaces of infinitely many dimensions) and possibly because more progress with difficult nonlinear problems has been made here than elsewhere. See also Hamilton's principle; Least-action principle.
Much of the work on the calculus of variations is devoted to meticulous detail with regard to the number of derivatives assumed to be available for various functions, particularly the competitive admissible functions y(x). If too many derivatives are assumed, minima may not exist; if too few are assumed, the solution might not be sufficiently smooth to be acceptable in the light of the original statement of the problem. In an attempt to use fewer derivatives, different approaches are used depending on the number of independent variables x.
| Columbia Encyclopedia: calculus of variations |
| Wikipedia: Calculus of variations |
Calculus of variations is a field of mathematics that deals with functionals, as opposed to ordinary calculus which deals with functions. Such functionals can for example be formed as integrals involving an unknown function and its derivatives. The interest is in extremal functions – those making the functional attain a maximum or minimum value – or stationary functions – those where the rate of change of the functional is precisely zero.
Perhaps the simplest example of such a problem is to find the curve of shortest length connecting two points. If there are no constraints, the solution is obviously a straight line between the points. However, if the curve is constrained to lie on a surface in space, then the solution is less obvious, and possibly many solutions may exist. Such solutions are known as geodesics. A related problem is posed by Fermat's principle: light follows the path of shortest optical length connecting two points, where the optical length depends upon the material of the medium. One corresponding concept in mechanics is the principle of least action.
Many important problems involve functions of several variables. Solutions of boundary value problems for the Laplace equation satisfy the Dirichlet principle. Plateau's problem requires finding a surface of minimal area that spans a given contour in space: the solution or solutions can often be found by dipping a wire frame in a solution of soap suds. Although such experiments are relatively easy to perform, their mathematical interpretation is far from simple: there may be more than one locally minimizing surface, and they may have non-trivial topology.
Contents |
The supremum norm (also called infinity norm) for real, continuous, bounded functions on a topological space X is defined as
.A functional J(y) defined on some appropriate space of functions V with norm
is said to have a weak minimum at the function y0 if there exists some δ > 0 such that, for all functions y with
,
.Weak maxima are defined similarly, with the inequality in the last equation reversed. In most problems, V is the space of r-times continuously differentiable functions on a compact subset E of the real line, with its norm given by
.This norm is just the sum of the supremum norms of y and its derivatives.
A functional J is said to have a strong minimum at y0 if there exists some δ > 0 such that, for all functions y with
,
. Strong maximum is defined similarly, but with the inequality in the last equation reversed.
The difference between strong and weak extrema is that, for a strong extremum, y0 is a local extremum relative to the set of δ-close functions with respect to the supremum norm. In general this (supremum) norm is different from the norm
that V has been endowed with. If y0 is a strong extremum for J then it is also a weak extremum, but the converse may not hold. Finding strong extrema is more difficult than finding weak extrema and in what follows it will be assumed that we are looking for weak extrema.
Under ideal conditions, the maxima and minima of a given function may be located by finding the points where its derivative vanishes. By analogy, solutions of smooth variational problems may be obtained by solving the associated Euler–Lagrange equation. In order to illustrate this process, consider the problem of finding the shortest curve in the plane that connects two points (x1,y1) and (x2,y2). The arc length is given by
![A[f] = \int_{x_1}^{x_2} \sqrt{1 + [ f'(x) ]^2} \, dx,](http://wpcontent.answers.com/math/6/f/e/6feb16a2b3bd7bbc98cbedfa6f84549c.png)
with

and where y = f(x), f(x1) = y1 and f(x2) = y2. The function f should have at least one derivative in order to satisfy the requirements for valid application of the function, further, if functional A[f] attain its local minimum at f0 and f1 is an arbitrary function that vanishes at the endpoints x1 and x2 and with at least one derivative, then we must have
![A[f_0] \le A[f_0 + \epsilon f_1]](http://wpcontent.answers.com/math/a/7/0/a7052a0ee93787a7fa54f9f4361b71c5.png)
for any number ε close to 0. Therefore, the derivative of A[f0 + εf1] with respect to ε (the first variation of A) must vanish at ε=0. Thus
![\int_{x_1}^{x_2} \frac{ f_0'(x) f_1'(x) } {\sqrt{1 + [ f_0'(x) ]^2}}\,dx =0, \,](http://wpcontent.answers.com/math/4/c/5/4c51b1cecda0f61d5af237739fe8b9ea.png)
for any choice of the function f1. We may interpret this condition as the vanishing of all directional derivatives of A[f0] in the space of differentiable functions, and this is formalized by requiring the Fréchet derivative of A to vanish at f0. If we assume that f0 has two continuous derivatives (or if we consider weak derivatives), then we may use integration by parts:
![\int_a^b u(x) v'(x)\,dx = \left[ u(x) v(x) \right]_{a}^{b} - \int_a^b u'(x) v(x)\,dx](http://wpcontent.answers.com/math/8/e/c/8ec2b3aec74713e8882e1fd6836e92f8.png)
with the substitution
![u(x)=\frac{ f_0'(x)} {\sqrt{1 + [ f_0'(x) ]^2}}, \quad v'(x)=f_1'(x),](http://wpcontent.answers.com/math/9/4/2/942eb6c4159a48e29a37cc838cdc3391.png)
then we have
![\left[ u(x) v(x) \right]_{x_1}^{x_2} - \int_{x_1}^{x_2} f_1(x) \frac{d}{dx}\left[ \frac{ f_0'(x) } {\sqrt{1 + [ f_0'(x) ]^2}} \right] \, dx =0,](http://wpcontent.answers.com/math/6/1/1/611b801d2bc0dc59272d41601492592a.png)
but the first term is zero since v(x) = f1(x) was chosen to vanish at x1 and x2 where the evaluation is taken. Therefore,
![\int_{x_1}^{x_2} f_1(x) \frac{d}{dx}\left[ \frac{ f_0'(x) } {\sqrt{1 + [ f_0'(x) ]^2}} \right] \, dx =0](http://wpcontent.answers.com/math/3/2/e/32e0b3f06761fffc0b392991205c6283.png)
for any twice differentiable function f1 that vanishes at the endpoints of the interval.
We can now apply the fundamental lemma of calculus of variations: If

for any sufficiently differentiable function f1(x) within the integration range that vanishes at the endpoints of the interval, then it follows that H(x) is identically zero on its domain.
Therefore,
![\frac{d}{dx}\left[ \frac{ f_0'(x) } {\sqrt{1 + [ f_0'(x) ]^2}} \right] =0.\,](http://wpcontent.answers.com/math/f/6/4/f6494bcff56ff347f99890bb7f99b5ba.png)
It follows from this equation that

and hence the extremals are straight lines.
A similar calculation holds in the general case where
![A[f] = \int_{x_1}^{x_2} L(x,f,f')\, dx . \,](http://wpcontent.answers.com/math/4/7/c/47c4d0db0092a1eff784737199e529af.png)
and f is required to have two continuous derivatives. Again, we find an extremal f0 by setting f = f0 + εf1, taking the derivative with respect to ε, and setting ε = 0 at the end:

where we have used the chain rule in the second line and integration by parts in the third. As before, the last term in the third line vanishes due to our choice of f1. Finally, according to the fundamental lemma of calculus of variations, we find that L will satisfy the Euler–Lagrange equation

In general this gives a second-order ordinary differential equation which can be solved to obtain the extremal f. The Euler–Lagrange equation is a necessary, but not sufficient, condition for an extremal. Sufficient conditions for an extremal are discussed in the references.
Frequently in physical problems, it turns out that
. In that case, the Euler-Lagrange equation can be simplified using the Beltrami identity:
where C is a constant. The left hand side is the Legendre transformation of L with respect to f '.
The discussion thus far has assumed that extremal functions possess two continuous derivatives, although the existence of the integral A requires only first derivatives of trial functions. The condition that the first variation vanish at an extremal may be regarded as a weak form of the Euler-Lagrange equation. The theorem of du Bois Reymond asserts that this weak form implies the strong form. If L has continuous first and second derivatives with respect to all of its arguments, and if

then f0 has two continuous derivatives, and it satisfies the Euler-Lagrange equation.
Fermat's principle states that light takes a path that (locally) minimizes the optical length between its endpoints. If the x-coordinate is chosen as the parameter along the path, and y = f(x) along the path, then the optical length is given by
![A[f] = \int_{x=x_0}^{x_1} n(x,f(x)) \sqrt{1 + f'(x)^2} dx, \,](http://wpcontent.answers.com/math/5/8/0/580d42c14a54cbffb03a5c8b8ed46f5e.png)
where the refractive index n(x,y) depends upon the material. If we try f(x) = f0(x) + εf1(x) then the first variation of A (the derivative of A with respect to ε) is
![\delta A[f_0,f_1] = \int_{x=x_0}^{x_1} \left[ \frac{ n(x,f_0) f_0'(x) f_1'(x)}{\sqrt{1 + f_0'(x)^2}} + n_y (x,f_0) f_1 \sqrt{1 + f_0'(x)^2} \right] dx.](http://wpcontent.answers.com/math/2/1/0/210d635eb8a64b43245a83028e48c9aa.png)
After integration by parts of the first term within brackets, we obtain the Euler-Lagrange equation
![-\frac{d}{dx} \left[\frac{ n(x,f_0) f_0'}{\sqrt{1 + f_0'^2}} \right] + n_y (x,f_0) \sqrt{1 + f_0'(x)^2} =0. \,](http://wpcontent.answers.com/math/9/e/5/9e5f2dd2c252fd63902084adc0fcafa4.png)
The light rays may be determined by integrating this equation.
There is a discontinuity of the refractive index when light enters or leaves a lens. Let


where n − and n + are constants. Then the Euler-Lagrange equation holds as before in the region where x<0 or x>0, and in fact the path is a straight line there, since the refractive index is constant. At the x=0, f must be continuous, but f' may be discontinuous. After integration by parts in the separate regions and using the Euler-Lagrange equations, the first variation takes the form
![\delta A[f_0,f_1] = f_1(0)\left[ n_-\frac{f_0'(0_-)}{\sqrt{1 + f_0'(0_-)^2}} -n_+\frac{f_0'(0_+)}{\sqrt{1 + f_0'(0_+)^2}} \right].\,](http://wpcontent.answers.com/math/8/e/b/8eb9b456a6f9c829395137dbd35c14ad.png)
The factor multiplying n − is the sine of angle of the incident ray with the x axis, and the factor multiplying n + is the sine of angle of the refracted ray with the x axis. Snell's law for refraction requires that these terms be equal. As this calculation demonstrates, Snell's law is equivalent to vanishing of the first variation of the optical path length.
It is expedient to use vector notation: let X = (x1,x2,x3), let t be a parameter, let X(t) be the parametric representation of a curve C, and let
be its tangent vector. The optical length of the curve is given by
![A[C] = \int_{t=t_0}^{t_1} n(X) \sqrt{ \dot X \cdot \dot X} dt. \,](http://wpcontent.answers.com/math/c/5/5/c551e541c87a4a9d1e3e9987e4fe1f88.png)
Note that this integral is invariant with respect to changes in the parametric representation of C. The Euler-Lagrange equations for a minimizing curve have the symmetric form

where

It follows from the definition that P satisfies

Therefore the integral may also be written as
![A[C] = \int_{t=t_0}^{t_1} P \cdot \dot X \, dt.\,](http://wpcontent.answers.com/math/c/8/3/c83e30cdfc936db5d5e1bc007868b9c2.png)
This form suggests that if we can find a function ψ whose gradient is given by P, then the integral A is given by the difference of ψ at the endpoints of the interval of integration. Thus the problem of studying the curves that make the integral stationary can be related to the study of the level surfaces of ψ. In order to find such a function, we turn to the wave equation, which governs the propagation of light.
The wave equation for an inhomogeneous medium is

where c is the velocity, which generally depends upon X. Wave fronts for light are characteristic surfaces for this partial differential equation: they satisfy

We may look for solutions in the form

In that case, ψ satisfies

where n = 1 / c. According to the theory of first order partial differential equations, if
then P satisfies

along a system of curves (the light rays) that are given by

These equations for solution of a first-order partial differential equation are identical to the Euler-Lagrange equations if we make the identification

We conclude that the function ψ is the value of the minimizing integral A as a function of the upper end point. That is, when a family of minimizing curves is constructed, the values of the optical length satisfy the characteristic equation corresponding the wave equation. Hence, solving the associated partial differential equation of first order is equivalent to finding families of solutions of the variational problem. This is the essential content of the Hamilton-Jacobi theory, which applies to more general variational problems.
The action was defined by Hamilton to be the time integral of the Lagrangian, L, which is defined as a difference of energies:

where T is the kinetic energy of a mechanical system and U is the potential energy. Hamilton's principle (or the action principle) states that the motion of a mechanical system is such that the action integral
![A[C] = \int_{t=t_0}^{t_1} L(x, \dot x, t) dt \,](http://wpcontent.answers.com/math/e/c/1/ec1a5df3fad2de4240b4215cab75325f.png)
is stationary with respect to variations in the path x(t). The Euler-Lagrange equations for this system are known as Lagrange's equations:

and they are equivalent to Newton's equations of motion.
The conjugate momenta P are defined by

For example, if

then

Hamiltonian mechanics results if the conjugate momenta are introduced in place of
, and the Lagrangian L is replaced by the Hamiltonian H defined by

The Hamiltonian is the total energy of the system: H = T + U. Analogy with Fermat's principle suggests that solutions of Lagrange's equations (the particle trajectories) may be described in terms of level surfaces of some function of X. This function is a solution of the Hamilton-Jacobi equation:

Variational problems that involve multiple integrals arise in numerous applications. For example, if φ(x,y) denotes the displacement of a membrane above the domain D in the x,y plane, then its potential energy is proportional to its surface area:
![U[\varphi] = \iint_D \sqrt{1 +\nabla \varphi \cdot \nabla \varphi} dx\,dy.\,](http://wpcontent.answers.com/math/b/4/8/b48b5eae93748f7aece52a696b3972d9.png)
Plateau's problem consists of finding a function that minimizes the surface area while assuming prescribed values on the boundary of D; the solutions are called minimal surfaces. The Euler-Lagrange equation for this problem is nonlinear:

See Courant (1950) for details.
It is often sufficient to consider only small displacements of the membrane, whose energy difference from no displacement is approximated by
![V[\varphi] = \frac{1}{2}\iint_D \nabla \varphi \cdot \nabla \varphi \, dx\, dy.\,](http://wpcontent.answers.com/math/a/d/d/addab64900cb5ec8eeaa1c21b9becf0d.png)
The functional V is to be minimized among all trial functions φ that assume prescribed values on the boundary of D. If u is the minimizing function and v is an arbitrary smooth function that vanishes on the boundary of D, then the first variation of V[u + εv] must vanish:
![\frac{d}{d\epsilon} V[u + \epsilon v]|_{\epsilon=0} = \iint_D \nabla u \cdot \nabla v \, dx\,dy = 0.\,](http://wpcontent.answers.com/math/3/8/6/386293fee819efb631626acde3ddf2ce.png)
Provided that u has two derivatives, we may apply the divergence theorem to obtain

where C is the boundary of D, s is arclength along C and
is the normal derivative of u on C. Since v vanishes on C and the first variation vanishes, the result is

for all smooth functions v that vanish on the boundary of D. The proof for the case of one dimensional integrals may be adapted to this case to show that
in D.The difficulty with this reasoning is the assumption that the minimizing function u must have two derivatives. Riemann argued that the existence of a smooth minimizing function was assured by the connection with the physical problem: membranes do indeed assume configurations with minimal potential energy. Riemann named this idea Dirichlet's principle in honor of his teacher Dirichlet. However Weierstrass gave an example of a variational problem with no solution: minimize
![W[\varphi] = \int_{-1}^{1} (x\varphi')^2 \, dx\,](http://wpcontent.answers.com/math/b/6/1/b61baae6a5e4468e2ec1acc6483b843b.png)
among all functions φ that satisfy
and
W can be made arbitrarily small by choosing piecewise linear functions that make a transition between -1 and 1 in a small neighborhood of the origin. However, there is no function that makes W=0. The resulting controversy over the validity of Dirichlet's principle is explained in http://turnbull.mcs.st-and.ac.uk/~history/Biographies/Riemann.html . Eventually it was shown that Dirichlet's principle is valid, but it requires a sophisticated application of the regularity theory for elliptic partial differential equations; see Jost and Li-Jost (1998).
A more general expression for the potential energy of a membrane is
![V[\varphi] = \iint_D \left[ \frac{1}{2} \nabla \varphi \cdot \nabla \varphi + f(x,y) \varphi \right] \, dx\,dy \, + \int_C \left[ \frac{1}{2} \sigma(s) \varphi^2 + g(s) \varphi \right] \, ds.](http://wpcontent.answers.com/math/0/1/b/01b45805f45fc97e4d4934889a6c1117.png)
This corresponds to an external force density f(x,y) in D, an external force g(s) on the boundary C, and elastic forces with modulus σ(s) acting on C. The function that minimizes the potential energy with no restriction on its boundary values will be denoted by u. Provided that f and g are continuous, regularity theory implies that the minimizing function u will have two derivatives. In taking the first variation, no boundary condition need be imposed on the increment v. The first variation of V[u + εv] is given by
![\iint_D \left[ \nabla u \cdot \nabla v + f v \right] \, dx\, dy + \int_C \left[ \sigma u v + g v \right] \, ds =0. \,](http://wpcontent.answers.com/math/3/f/a/3fa442a42a031bcf496d8020f29d7d8d.png)
If we apply the divergence theorem, the result is
![\iint_D \left[ -v \nabla \cdot \nabla u + v f \right] \, dx \, dy + \int_C v \left[ \frac{\part u}{\part n} + \sigma u + g \right] \, ds =0. \,](http://wpcontent.answers.com/math/c/f/c/cfc5f8d15b04f8e23d974e5b7eb154f2.png)
If we first set v=0 on C, the boundary integral vanishes, and we conclude as before that

in D. Then if we allow v to assume arbitrary boundary values, this implies that u must satisfy the boundary condition

on C. Note that this boundary condition is a consequence of the minimizing property of u: it is not imposed beforehand. Such conditions are called natural boundary conditions.
The preceding reasoning is not valid if σ vanishes identically on C. In such a case, we could allow a trial function
, where c is a constant. For such a trial function,
![V[c] = c\left[ \iint_D f \, dx\,dy + \int_C g ds \right].](http://wpcontent.answers.com/math/f/b/7/fb79ff30783e419c7540db7eac104533.png)
By appropriate choice of c, V can assume any value unless the quantity inside the brackets vanishes. Therefore the variational problem is meaningless unless

This condition implies that net external forces on the system are in equilibrium. If these forces are in equilibrium, then the variational problem has a solution, but it is not unique, since an arbitrary constant may be added. Further details and examples are in Courant and Hilbert (1953).
Both one-dimensional and multi-dimensional eigenvalue problems can be formulated as variational problems.
The Sturm-Liouville eigenvalue problem involves a general quadratic form
![Q[\varphi] = \int_{x_1}^{x_2} \left[ p(x) \varphi'(x)^2 + q(x) \varphi(x)^2 \right] \, dx, \,](http://wpcontent.answers.com/math/b/1/5/b155451d196b039ddf18750be8a8311a.png)
where φ is restricted to functions that satisfy the boundary conditions

Let R be a normalization integral
![R[\varphi] =\int_{x_1}^{x_2} r(x)\varphi(x)^2 \, dx.\,](http://wpcontent.answers.com/math/7/7/5/775d51c4b350ec3d1e1b2b5d89e6b226.png)
The functions p(x) and r(x) are required to be everywhere positive and bounded away from zero. The primary variational problem is to minimize the ratio Q/R among all φ satisfying the endpoint conditions. It is shown below that the Euler-Lagrange equation for the minimizing u is

where λ is the quotient
![\lambda = \frac{Q[u]}{R[u]}. \,](http://wpcontent.answers.com/math/6/7/0/6703e4c62e106143cf003abaf1888b84.png)
It can be shown (see Gelfand and Fomin 1963) that the minimizing u has two derivatives and satisfies the Euler-Lagrange equation. The associated λ will be denoted by λ1; it is the lowest eigenvalue for this equation and boundary conditions. The associated minimizing function will be denoted by u1(x). This variational characterization of eigenvalues leads to the Rayleigh-Ritz method: choose an approximating u as a linear combination of basis functions (for example trigonometric functions) and carry out a finite-dimensional minimization among such linear combinations. This method is often surprisingly accurate.
The next smallest eigenvalue and eigenfunction can be obtained by minimizing Q under the additional constraint

This procedure can be extended to obtain the complete sequence of eigenvalues and eigenfunctions for the problem.
The variational problem also applies to more general boundary conditions. Instead of requiring that φ vanish at the endpoints, we may not impose any condition at the endpoints, and set
![Q[\varphi] = \int_{x_1}^{x_2} \left[ p(x) \varphi'(x)^2 + q(x)\varphi(x)^2 \right] \, dx + a_1 \varphi(x_1)^2 + a_2 \varphi(x_2)^2, \,](http://wpcontent.answers.com/math/0/6/9/069ee4eed7b3ac2771e01101de8309bd.png)
where a1 and a2 are arbitrary. If we set
the first variation for the ratio Q / R is
![V_1 = \frac{2}{R[u]} \left( \int_{x_1}^{x_2} \left[ p(x) u'(x)v'(x) + q(x)u(x)v(x) -\lambda u(x) v(x) \right] \, dx + a_1 u(x_1)v(x_1) + a_2 u(x_2)v(x_2) \right) , \,](http://wpcontent.answers.com/math/2/4/5/245545be5020f92b961e187b48d93d61.png)
where λ is given by the ratio Q[u] / R[u] as previously. After integration by parts,
![\frac{R[u]}{2} V_1 = \int_{x_1}^{x_2} v(x) \left[ -(p u')' + q u -\lambda r u \right] \, dx + v(x_1)[ -p(x_1)u'(x_1) + a_1 u(x_1)] + v(x_2) [p(x_2 u'(x_2) + a_2 u(x_2). \,](http://wpcontent.answers.com/math/a/f/b/afbe26976a50355285da741c78fea333.png)
If we first require that v vanish at the endpoints, the first variation will vanish for all such v only if

If u satisfies this condition, then the first variation will vanish for arbitrary v only if

These latter conditions are the natural boundary conditions for this problem, since they are not imposed on trial functions for the minimization, but are instead a consequence of the minimization.
Eigenvalue problems in higher dimensions are defined in analogy with the one-dimensional case. For example, given a domain D with boundary B in three dimensions we may define
![Q[\varphi] = \iiint_D p(X) \nabla \varphi \cdot \nabla \varphi + q(X) \varphi^2 \, dx \, dy \, dz + \iint_B \sigma(S) \varphi^2 \, dS, \,](http://wpcontent.answers.com/math/3/e/6/3e61f4738d040f40016489a67e01b0ce.png)
and
![R[\varphi] = \iiint_D r(X) \varphi(X)^2 \, dx \, dy \, dz.\,](http://wpcontent.answers.com/math/d/6/4/d645b874f8c5dd10c3b760cb0a603b94.png)
Let u be the function that minimizes the quotient
with no condition prescribed on the boundary B. The Euler-Lagrange equation satisfied by u is

where
![\lambda = \frac{Q[u]}{R[u]}.\,](http://wpcontent.answers.com/math/6/7/0/6703e4c62e106143cf003abaf1888b84.png)
The minimizing u must also satisfy the natural boundary condition

on the boundary B. This result depends upon the regularity theory for elliptic partial differential equations; see Jost and Li-Jost (1998) for details. Many extensions, including completeness results, asymptotic properties of the eigenvalues and results concerning the nodes of the eigenfunctions are in Courant and Hilbert (1953).
This entry is from Wikipedia, the leading user-contributed encyclopedia. It may not have been reviewed by professional editors (see full disclaimer)
| Best of the Web: calculus of variations |
Some good "calculus of variations" pages on the web:
Math mathworld.wolfram.com |
| critical function (mathematics) | |
| Jacobi condition (mathematics) | |
| isoperimetric problem (mathematics) |
| What is calculus and what does it have to do with? Read answer... | |
| What does a variator do? Read answer... | |
| What is Pre calculus? Read answer... |
Copyrights:
![]() | Dictionary. The American Heritage® Dictionary of the English Language, Fourth Edition Copyright © 2007, 2000 by Houghton Mifflin Company. Updated in 2009. Published by Houghton Mifflin Company. All rights reserved. Read more | |
![]() | Sci-Tech Encyclopedia. McGraw-Hill Encyclopedia of Science and Technology. Copyright © 2005 by The McGraw-Hill Companies, Inc. All rights reserved. Read more | |
![]() | Columbia Encyclopedia. The Columbia Electronic Encyclopedia, Sixth Edition Copyright © 2003, Columbia University Press. Licensed from Columbia University Press. All rights reserved. www.cc.columbia.edu/cu/cup/. Read more | |
![]() | Wikipedia. This article is licensed under the Creative Commons Attribution/Share-Alike License. It uses material from the Wikipedia article "Calculus of variations". Read more |
Mentioned in