Share on Facebook Share on Twitter Email
Answers.com

Circular segment

 
Sci-Tech Dictionary: circular segment
(′sər·kyə·lər ′seg·mənt)

(mathematics) Portion of circle cut off from the main body of the circle by a straight line (chord) through the circle.


Search unanswered questions...
Enter a question here...
Search: All sources Community Q&A Reference topics
Wikipedia: Circular segment
Top

In geometry, a circular segment (also circle segment) is an area of a circle informally defined as an area which is "cut off" from the rest of the circle by a secant or a chord. The circle segment constitutes the part between the secant and an arc, excluding the circle's center.

Contents

Formula

A circular segment (shown here in green) is enclosed between a secant/chord (the dashed line) and the arc whose endpoints equal the chord's (the arc shown above the green area).

Let R be the radius of the circle, c the chord length, s the arc length, h the height of the segment, and d the height of the triangular portion. The area of the circular segment is equal to the area of the circular sector minus the area of the triangular portion.

The radius is R = h + d \frac{}{}

The arc length is s = R \theta \frac{}{}, where  \theta \frac{}{} is in radians.

The area is A = \frac{R^2}{2}\left(\theta-\sin\theta\right)


The chord length is c = 2R\sin\frac{\theta}{2} = R\sqrt{2-2\cos\theta}

The height is h = R(1-\cos\frac{\theta}{2})

The angle is  \theta = 2\arccos\frac{d}{R}


Derivation of the area formula

The area of the circular sector is \pi R^2 \cdot \frac{\theta}{2\pi} = R^2\left(\frac{\theta}{2}\right)

If we bisect angle θ, and thus the triangular portion, we will get two triangles with the area \frac{1}{2} R\sin \frac{\theta}{2} R\cos \frac{\theta}{2} or 2\cdot\frac{1}{2}R\sin\frac{\theta}{2} R\cos\frac{\theta}{2}

= R^2\sin\frac{\theta}{2}\cos\frac{\theta}{2}

Since the area of the segment is the area of the sector decreased by the area of the triangular portion, we have

R^2\left(\frac{\theta}{2}-\sin\frac{\theta}{2}\cos\frac{\theta}{2}\right)

According to trigonometry, 2sinxcosx = sin2x, therefore

\sin\frac{\theta}{2}\cos\frac{\theta}{2} = \frac{1}{2}\sin\theta

The area is therefore:

R^2\left(\frac{\theta}{2}-\frac{1}{2}\sin\theta\right)

= \frac{R^2}{2}\left(\theta-\sin\theta\right)

See also

External links


Best of the Web: Circular segment
Top

Some good "Circular segment" pages on the web:


Math
mathworld.wolfram.com
 
 
 

 

Copyrights:

Sci-Tech Dictionary. McGraw-Hill Dictionary of Scientific and Technical Terms. Copyright © 2003, 1994, 1989, 1984, 1978, 1976, 1974 by McGraw-Hill Companies, Inc. All rights reserved.  Read more
Wikipedia. This article is licensed under the Creative Commons Attribution/Share-Alike License. It uses material from the Wikipedia article "Circular segment" Read more