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d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-1 d-0 a-3 a-2 a-1 a-0 d-3 d-2 d-1 d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-0 a-0 d-1 d-2 d-0 a-3(2)

(2)=2 beats [half note] the rest are 1 beat [quarter note]

d= the string on the violin (g,d,a,e)

-0=how many fingers you put on that string

hope this helps!!!!!! >_< hehe...... =P

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d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-1 d-0 a-3 a-2 a-1 a-0 d-3 d-2 d-1 d-0(2) d-0(2) d-1 d-3 d-2 d-1 a-0(2) a-0(2) a-0 a-1 d-2 d-3 d-1(2) d-1(2) d-1 d-3 d-2 d-0 a-0 d-1 d-2 d-0 a-3(2)

(2)=2 beats [half note] the rest are 1 beat [quarter note]

d= the string on the violin (g,d,a,e)

-0=how many fingers you put on that string

hope this helps!!!!!! >_< hehe...... =P

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-11

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In terms of variables, a ± d would be (a + d) or (a - d)

Example: if a = 1, and d = 2, then a ± d = 3 and a ± d = -1

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d/dx (1-x)=d/dx (1)-d/dx(x)=0-1=-1

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v = − 1/ a .d [A] /d t = − 1 /b .d [B] /d t = 1 /p. d [P]/ d t = 1/ q .d [Q]/ d t

for the "balanced" equation

aA + bB -> pP + qQ

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