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Not sure but could it be:-

Probability of selecting one day out of seven:-(1/7)

Now probability that only one person out of 10 watches the movie:-(1/10)

Thus the total probability of only one person watching the movie on any given day will be:- (1/7)*(1/10)=1/70

Now, the probability that at least two of them watch the movie on the same day will be:- 1-(1/70)=(69/70) Hope this works, Any other suggestions are welcome.

- Regards, NightHawk

This answer is:
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Not sure but could it be:-

Probability of selecting one day out of seven:-(1/7)

Now probability that only one person out of 10 watches the movie:-(1/10)

Thus the total probability of only one person watching the movie on any given day will be:- (1/7)*(1/10)=1/70

Now, the probability that at least two of them watch the movie on the same day will be:- 1-(1/70)=(69/70) Hope this works, Any other suggestions are welcome.

- Regards, NightHawk

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