Not sure but could it be:-
Probability of selecting one day out of seven:-(1/7)
Now probability that only one person out of 10 watches the movie:-(1/10)
Thus the total probability of only one person watching the movie on any given day will be:- (1/7)*(1/10)=1/70
Now, the probability that at least two of them watch the movie on the same day will be:- 1-(1/70)=(69/70) Hope this works, Any other suggestions are welcome.
- Regards, NightHawk