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# How does one determine the maximum energy to which a deuteron can be accelerated in a cyclotron?

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The final energy attained by a deuteron undergoing cyclotron acceleration depends on the design of the cyclotron. In some machines the final energy may be… as low as 3MeV whilst in others, 25MeV. Above 25MeV reletavistic effects kick-in and the cyclotron needs to be more sophisticated in its design..
It does depend on the cyclotron. Theres actually an equation for that. It takes into account the maximum radius of the orbit of the particles and the wavelength of the accelerating voltage. So for a given cyclotron with exactly specified values for radius and wavelength, the maximum kinetic energy of a particle depends on its rest energy and, hence, its rest mass. But heres an easy way to figure it out: If a given cyclotron can accelerate protons to an energy of say, 2 MeV, then deuterons can be accelerated to 4 MeV. Multiply by a factor of 2. (MORE)