There are four requirements that need to be satisfied:

A. Closure: For any two elements of the group, a and b, the operation a*b is also a member of the group.

B. Associativity: For any three members of the group, a*(b*c) = (a*b)*c

C. Identity: There exists an element in the group, called the identity and denoted by i, such that a*i = i*a for all a in the group. For real numbers with multiplication, this element is 1.

D. Inverse: For any member of the group, a, there exists a member of the group, b, such that a*b = b*a = 1 (the identity). b is called the inverse of a and denoted by a-1.

There are five groups of order 8: three of them are Abelian and the other two are not.

These are

1. C8, the group generated by a where a8 = 1

2. C4xC2, the group generated by a and b where a4 = b2 = 1

3. C2xC2xC2, the group generated by a, b and c where a2 = b2 = c2= 1

4. the dihedral group

5. the quaternion group

Yes, this is possible

the alleles for B-type are (I^B i ) or (I^B I^B )

for a perent to be O which alleles is (ii) the child should be (I^B i )

and in this way the child got the (i) from father, and I^B from mother.

If at a competition group "a" defeats group "b", and group "b" defeats group "c" then group "a" will have to defeat group "C"

You can use the "group by" expression using all fields that need to be considered unique. Then use the "having" expression equal to 1 to filter out the rows that are "distinct". select a,b,c,count(*) from sample_table group by a,b,c having count(*) = 1; A variation of this will give "distinct" values. select a,b,c from sample_table group by a,b,c