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f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

Q: How do you differentiate x over 2?

This answer is:

Related answers

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

f(x) = x/2

Then the differential is lim h->0 [f(x+h) - f(x)]/h

= lim h->0 [(x+h)/2 - x/2]/h

= lim h->0 [h/2]/h

= lim h->0 [1/2] = 1/2

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-1

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d/dh(h^-1) = -1(h^-2) = -(h^-2)

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H-H or H:H depending on what you and your professors prefer.

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Factor 2h−2

2h−2

=2(h−1)

Answer:

2(h−1)

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