I don't factor these. I am lazy, so I use the quadratic
formula.
-b +/- sqrt(b^2-4ac)/2a
a = 2
b = 13
c = 6
u = - 13 +/- sqrt[13^2 - 4(2)(6)]/2(2)
u = - 13 +/- sqrt(121)/4
u = [- 13 +/- 11]/4
u = - 1/2
u = - 6
My TI-84 confirms this answer. You check in original
equation.