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In Numbers

Irrational numbers are numbers that cannot be expressed as fractions with whole numbers. They are generally roots (such as the square root of two) or constants (such as pi and… e). They are interesting because they cannot be exactly expressed as decimal numbers because they never terminate or repeat themselves. (MORE)

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In Numbers

The product of two irrational numbers may be rational or irrational. For example, sqrt(2) is irrational, and sqrt(2)*sqrt(2) = 2, a rational number. On the other hand, (2^(1/4…)) * (2^(1/4)) = 2^(1/2) = sqrt(2), so here two irrational numbers multiply to give an irrational number. (MORE)

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In Numbers

Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of …2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4). (MORE)

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In Numbers

No. An irrational number can only be part of a whole number. Every whole number is rational. 1000000

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To many variables to determine. Consult a catalog, available online or at your local library. In most cases the value is going to be pretty low, as Washington is a common subj…ect for definitive stamps. But there are some with some good values to them! (MORE)

Are you a true American?
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Bottoms up!
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We will try to guess what is your most often mood.… (MORE)

Have a weak spot for boy bands? Find out which one is your group!… (MORE)

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In Technology

It does not come preloaded, but there are a few available for free in the App Store.

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Yes, but not always. An easy example is sqrt(2) + sqrt(2) + sqrt(2) = 3sqrt(2), an irrational number. An easy counterexample is 2sqrt(2) + -sqrt(2) + -sqrt(2) = 0, w…hich is rational. (MORE)

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In Numbers

It certainly can! All irrational numbers (numbers that can't be written as fractions, and in decimal form go endlessly without a pattern) are real (not divided by zero and not… connected to the square root of a negative number). (MORE)

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In Science

Yes. The proof is easy. Let x be the irrational number and assume there exists some rational number r = a/b where a and b are integers (that's what it means to be rational…). Now suppose x/r is a rational number. Then x/r = (b/a)x = c/d where c and d are some other integers. Since (b/a)x=c/d, then x = bd/ac which means that x itself is rational, but we assumed it was irrational. The contradiction proves that the assertion is wrong. An irrational divided by a rational must be irrational. (MORE)

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In Numbers

No, because if need be it can be expressed as a fraction whereas irrational numbers can't be expressed as fractions.