Ek=1/2mv**2

Ek=0.058*(10**8)**2

Ek=0.058*10**16

Ek=0.58 petajoules

Many, many, many, many different ways.

o = initial

First option: v=vo+at

Second option: v^2=vo^2+2a(x-xo)

Third option: y=yo+vot+(1/2)at^2

Fourth option: y=(v^2-vo^2)/(2a)

etc...

However, you will have to use your basic algebraic skills to isolate initial velocity.

Ek = 1/2 * m * v^2

Ek = 1/2 * 161 g * (39 m/s)^2

Ek = 1/2 * 161g * (1kg / 1000g) * (39 m/s)^2

Ek = 254 kgm^2/s^2

Ek = 254 J

2nd jan 2013 on life ok.

i actually want to know that 2 because im taking the test on Jan 17