answersLogoWhite

0

AllQ&AStudy Guides
Best answer

The geometric distribution is:

Pr(X=k) = (1-p)k-1p for k = 1, 2 , 3 ...

A geometric series is a+ ar+ ar2, ... or ar+ ar2, ...

Now the sum of all probability values of k = Pr(X=1) + Pr(X = 2) + Pr(X = 3) ...

= p + p2+p3 ... is a geometric series with a = 1 and the value 1 subtracted from the series.

See related links.

This answer is:
Related answers

The geometric distribution is:

Pr(X=k) = (1-p)k-1p for k = 1, 2 , 3 ...

A geometric series is a+ ar+ ar2, ... or ar+ ar2, ...

Now the sum of all probability values of k = Pr(X=1) + Pr(X = 2) + Pr(X = 3) ...

= p + p2+p3 ... is a geometric series with a = 1 and the value 1 subtracted from the series.

See related links.

View page

M I K A E L M I K A E L M I K A E L

View page

If the value given in the table for Z = z is k: that is, pr(Z > z) is 1 - k, then the two-tailed probability of observing a value which is at least as extreme, ie Pr(|Z| > z) is 0.5*(1-k).

View page

Ginger fox Gnu J J K K Jpuljji K L L L

View page

K. L. Dhammajoti was born in 1949.

View page
Featured study guide
📓
See all Study Guides
✍️
Create a Study Guide
Search results