0
Fe lix Marti nez Orejo n has written:
'Cuando las cruces no se alzan al cielo'
A very good try, but f(n) is still ambiguous. I assume you mean
f(n) = 1/2*n*(n+2) and not 1/[2*n*(n+2)]
Then f(n+2) - f(n) = 1/2*(n+2)*(n+2+2) - 1/2*n*(n+2)
= 1/2*(n+2)*(n+4) - 1/2*n*(n+2)
= 1/2*(n+2)*{(n + 4) - n}
= 1/2*(n+2)*4
= 2*(n+2)
N O F Ne He Cl Ar Kr Xe Rn
Yes, in increasing order B < C < N < O < F ( >>>> Ne )
LIX, or lix.