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Dr. Seuss .

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No, she never had children..She felt it would not be fair to her children if someone else had to take care of them...and she would not have enough time to devote to them...I t…hink more women should feel that way...Love you Stevie!! (MORE)

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J.K. Rowling, Dr Seuss, May Gibbs (Snugglepot and Cuddlepie) Lemony Snicket, Emily Rodda, Norman Lindsay (The Magic Pudding), Dorothy Wall (Blinky Bill), Enid Blyton, Keneth G…rahame (wind in the willows) and Stephanie Meyer (MORE)

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I had to read a biography on Avi, he had two of his own sons, Shaun and Kevin he also had a stepson from a different marriage ,his name is Gabriel

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Possibly you mean Robert Louis Stevenson, author of 'Treasure Island' and many others. how about RL Stine - wrote Goosebumps books Indeed, and there are probably oth…ers. Pushing the envelope - the Reverend Luttwidge Dodgson wrote under the name of 'Lewis Carrol'. (MORE)

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Advantage is that it has the most flat passband meaning that it is very good at simulating the passband of an ideal filter. The disadvantage is that it has a horrible stopba…nd because it gradually goes to zero so some parts of the stopband are still passed. However, for an nth-order Butterworth Filter, as n increases, the closer it is to an ideal filter. However, it is highly impractical to build a ridiculously high order Butterworth filter. (MORE)

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Butterworth filter works as an ideal low pass filter.Butterworth filter is best suited for the closed loop gain to be as close to 1 as possible within the passband.Roll-offs b…ecome steeper,they approach the ideal filter more closely. (MORE)

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% program to design butterworth low pass filter clc; clear all; close all; alphap=input ('enter the pass band ripple'); alphas=input('enter the stop band ripple'); … fp=input('enter the pass band freq'); fs=input('enter the stop band freq'); F=input('enter the sampling freq'); omp=2*fp/F;oms=2*fp/F; %to find cut off freq and order of the filter [n,wn]=buttord(omp,,oms,alphap,alphas); % system function of the filter [b,a]=butter(n,wn,'step'); w=0:0.01:pi; [h,om]=freq(b,a,w); m=2*log(abe(h)); an=angle(h); subplot(2,1,1); plot(om/pi,m); ylabel('magnitude'); xlabel(''om/pi); title('magnitude'); subplot(2,1,2); plot(om/pi,an); ylabel('phase angle'); xlabel('om/pi'); title('phase angle'); (MORE)

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the 5s because it has better service but it dosent have diffrent colrs just silver gold and black

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20c + 5 = 5c + 65 Divide through by 5: 4c + 1 = c + 13 Subtract c from both sides: 3c + 1 = 13 Subtract 1 from both sides: 3c = 12 Divide both sides by 3: c = 4