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58.1g [Ca(PO4)] X

1 mol [Ca(PO4)] X

2 mol (PO4) X

1 mol (P) X

30.97g (P)

= 11.6g (P)

310.2g [Ca(PO4)]

1 mol[Ca(PO4)]

1 mol (PO4)

1 mol (P)

Sorry about the formatting, im trying to show stoichiometry.

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Related answers

58.1g [Ca(PO4)] X

1 mol [Ca(PO4)] X

2 mol (PO4) X

1 mol (P) X

30.97g (P)

= 11.6g (P)

310.2g [Ca(PO4)]

1 mol[Ca(PO4)]

1 mol (PO4)

1 mol (P)

Sorry about the formatting, im trying to show stoichiometry.

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Ca & P

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P and S as they are non metals.

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Paula, Ca

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panorama city,CA

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