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p e e p e e p o o p o o OUuuOOuuuoOOO

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p e e p e e p o o p o o OUuuOOuuuoOOO

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If the odd favoring an event are 10 to 1, then the probability of the event occurring is 0.9.

The odds in favor of an event are 10:1.

Find the probability that the event will occur.

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P(E)+P(E') = 1

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P(E)/P(E') = 10/1

So P(E) = 10P(E')

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Substitute for P(E) and solve for P(E'):

10P(E')+P(E') = 1

11P(E') = 1

P(E') = 1/11

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Therefore P(E) = 10/11

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What is N E P?

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P-I-N-E-A-P-P-L-E

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If: E*I = P

Then: I = P/E

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