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The Peak inverse voltage (PIV) equals the peak value of the input voltage, and the diode must be capable of withstanding this amount of repetition reverse voltage. For the diode in figure, the maximum value of reverse voltage, designated as PIV, occurs at peak of each positive alternation of the input voltage when the diode is forward biased.

Peak Inverse Voltage at Positive Half Cycle

The Peak Inverse Voltage (PIV) occurs at the peak of each half-cycle of the input voltage when the diode is forward biased . In this circuit, the PIV occurs at the peak of each positive half cycle.

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The Peak inverse voltage (PIV) equals the peak value of the input voltage, and the diode must be capable of withstanding this amount of repetition reverse voltage. For the diode in figure, the maximum value of reverse voltage, designated as PIV, occurs at peak of each positive alternation of the input voltage when the diode is forward biased.

Peak Inverse Voltage at Positive Half Cycle

The Peak Inverse Voltage (PIV) occurs at the peak of each half-cycle of the input voltage when the diode is forward biased . In this circuit, the PIV occurs at the peak of each positive half cycle.

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Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.

Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".

Answer

'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.

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You measure the peak to peak voltage and divide by 2.

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v peak = v rms times square root (2)

Note: A junction voltage of 0.3V is atypical. Normally a silicon diode has a forward voltage between 0.6 volts to 1.4V depending on current. Are you sure about the forward voltage? Perhaps you are talking about germanium or schottky diodes?

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Simply multiply the peak voltage to 2 and you will get the peak to peak voltage.

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