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actually there are specific formulea for inverse LT..it is just like LT..u just have to reverse the process.... eg. L[1]=1/s ILT[1/s]= 1 thats so simple..u just have to reme…mber the formulea.... (MORE)

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In Technology

We are using integrated circuits inside the CPU. Laplace Transformations helps to find out the current and some criteria for the analysing the circuits... So, in computer fiel…d Laplace tranformations plays vital role... (MORE)

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In Education

z transform is used for the digital signals and laplace is generally used of the contineous signals.

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In Algebra

gonna keep this short and 2 the point .. i had the same question and i found this webpage .. it helped me a lot .. so try reading it hope it helps u out .. www.dartmouth….edu/~sullivan/22files/Laplace_Transforms.pdf (MORE)

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In Technology

The most generalized reason would be: "To solve initial-valued differential equations of the 2nd (or higher) order." Laplace is a little powerful for 1st order, but it …will solve them as well. There is a limitation here: Laplace will only generate an exact answer if initial conditions are provided. Laplace cannot be used for boundary-valued problems. In terms of electronics engineering, the Laplace transform is used to get your model into the s-domain, so that s-domain analysis may be performed (finding zeroes and poles of your characteristic equation). This is particularly useful if one needs to determine the kind of response an RC, RLC, or LC circuit will provide (i.e. underdamped, overdamped, critically damped). Once in the s-domain, we may begin discussing the components in terms of impedance. Sometimes it is easier to calculate the voltage or current across a capacitor or an inductor in terms of the components' impedances, rather than find it in a t-domain model. The node-voltage and mesh-current methods used to analyze a circuit in the t-domain work in the s-domain as well. (MORE)

As it turns out, these stars actually regret the roles responsible for launching their careers into unforgettable stardom. After you read our explanations, perhaps you'll unde…rstand why. (MORE)

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When it comes to basic facts, what you don't know can hurt you, or at the very least surprise you.… (MORE)

As the saying goes, you can't teach an old dog new tricks. Some tricks, however, are so simple that even an old dog or new puppy can learn them. Just practice any of the follo…wing a few times a day with your dog. (MORE)

While traveling with a dog down the open road makes for good memories, doing it properly takes some thought. Help you and your dog enjoy the time you spend journeying together… by keeping these tips in mind. (MORE)

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the difference is the "S" and "Z" parameters. S used for analog computation while Z for digital processing. basically Z is the digital approximation of the analog frequenc…y domain signal. Z=exp(sT) where T is the sampling time. (MORE)

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In Uncategorized

the 5s because it has better service but it dosent have diffrent colrs just silver gold and black

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In Science

Laplace law defines that when a reaction is done ,the enthalpy change remains same to the enthalpy change when done in the reverse direction but the change in ebthalpy have op…posite signs. H2 + 1/2 O2 ----> H2O ....dH=-285.1j H2O -----> H2 + 1/2 O2 .....dH.... +285.1j (MORE)

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In Science

He formulated Laplace's equation, and pioneered the Laplace transform which appears in many branches of mathematical physics, a field that he took a leading role in forming. T…he Laplacian differential operator, widely used in mathematics, is also named after him. He restated and developed the nebular hypothesis of the origin of the solar system and was one of the first scientists to postulate the existence of black holes and the notion of gravitational collapse. And much more... (MORE)

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In Calculus

The Laplace transform is a widely used integral transform in mathematics with many applications in physics and engineering. It is a linear operator of a function f(t) with… a real argument t (t ≥ 0) that transforms f(t) to a function F(s) with complex argument s, given by the integral F(s) = \\int_0^\\infty f(t) e^{-st}\\,dt. (MORE)