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sufficiency

 
Dictionary: suf·fi·cien·cy   (sə-fĭsh'ən-sē) pronunciation
 
n., pl. -cies.
  1. The condition or quality of being sufficient.
  2. An adequate amount or quantity.
  3. Adequate means to live in modest comfort.

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Thesaurus: sufficiency
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noun

    An adequate quantity: adequacy, enough. See excess/insufficiency/enough.

 
WordNet: sufficiency
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Note: click on a word meaning below to see its connections and related words.

The noun has 3 meanings:

Meaning #1: sufficient resources to provide comfort and meet obligations

Meaning #2: an adequate quantity; a quantity that is large enough to achieve a purpose
  Synonym: enough

Meaning #3: the quality of being sufficient for the end in view
  Synonym: adequacy
  Antonym: insufficiency (meaning #3)


 
Wikipedia: Sufficiency (statistics)
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In statistics, sufficiency is the property possessed by a statistic, with respect to a parameter, "when no other statistic which can be calculated from the same sample provides any additional information as to the value of the parameter".[1]

This concept was due to Sir Ronald Fisher, and is equivalent to the most general statement of the above that, conditional on the value of a sufficient statistic, the distribution of data is not a function of the underlying parameter(s) the statistic is sufficient for. Both the statistic and the underlying parameter can be vectors.

The concept has fallen out of favor in descriptive statistics because of the strong dependence on an assumption of the distributional form (see Pitman-Koopman-Darmois theorem below), but remains very important in theoretical work.[2]

Contents

Mathematical definition

The concept is most general when defined as follows: a statistic T(X) is sufficient for underlying parameter θ precisely if the conditional probability distribution of the data X, given the statistic T(X), is not a function of the parameter θ,[3] i.e.

\Pr(X=x|T(X)=t,\theta) = \Pr(X=x|T(X)=t), \,

or in shorthand

\Pr(x|t,\theta) = \Pr(x|t).\,

Example

As an example, the sample mean is sufficient for the mean (μ) of a normal distribution with known variance. Once the sample mean is known, no further information about μ can be obtained from the sample itself.

Fisher–Neyman factorization theorem

Fisher's factorization theorem or factorization criterion provides a convenient characterization of a sufficient statistic. If the probability density function is ƒθ(x), then T is sufficient for θ if and only if functions g and h can be found such that

 f_\theta(x)=h(x) \, g_\theta(T(x)), \,\!

i.e. the density ƒ can be factored into a product such that one factor, h, does not depend on θ and the other factor, which does depend on θ, depends on x only through T(x).

Interpretation

An implication of the theorem is that when using likelihood-based inference, two sets of data yielding the same value for the sufficient statistic T(X) will always yield the same inferences about θ. By the factorization criterion, the likelihood's dependence on θ is only in conjunction with T(X). As this is the same in both cases, the dependence on θ will be the same as well, leading to identical inferences.

Proof

Due to Hogg and Craig (ISBN 978-0023557224). Let X1, X2, ..., Xn, denote a random sample from a distribution having the pdf f(x,θ) for γ < θ < δ. Let Y = u(X1, X2, ..., Xn) be a statistic whose pdf is g(y;θ). Then Y = u(X1, X2, ..., Xn) is a sufficient statistic for θ if and only if, for some function H,

 \prod_{i=1}^{n} f(x_i; \theta) = g \left[u(x_1, x_2, \dots, x_n); \theta \right] H(x_1, x_2, \dots, x_n). \,\!

First, suppose that

 \prod_{i=1}^{n} f(x_i; \theta) = g \left[u(x_1, x_2, \dots, x_n); \theta \right] H(x_1, x_2, \dots, x_n). \,\!

We shall make the transformation yi = ui(x1, x2, ..., xn), for i = 1, ..., n, having inverse functions xi = wi(y1, y2, ..., yn), for i = 1, ..., n, and Jacobian  J = \left[w_i/y_j \right] . Thus,


 \prod_{i=1}^{n} f \left[ w_i(y_1, y_2, \dots, y_n); \theta \right]  = 
 |J| g(y; \theta) H \left[ w_1(y_1, y_2, \dots, y_n), \dots, w_n(y_1, y_2, \dots, y_n) \right].

The left-hand member is the joint pdf g(y1, y2, ..., yn; θ) of Y1 = u1(X1, ..., Xn), ..., Yn = un(X1, ..., Xn). In the right-hand member, g(y_1,\dots,y_n;\theta) is the pdf of Y1, so that H[ w_1, \dots , w_n] |J| is the quotient of g(y_1,\dots,y_n;\theta) and g1(y1;θ); that is, it is the conditional pdf h(y_2, \dots, y_n | y_1; \theta) of Y_2,\dots,Y_n given Y1 = y1.

But H(x_1,x_2,\dots,x_n), and thus H\left[w_1(y_1,\dots,y_n), \dots, w_n(y_1, \dots, y_n))\right], was given not to depend upon θ. Since θ was not introduced in the transformation and accordingly not in the Jacobian J, it follows that h(y_2, \dots, y_n | y_1; \theta) does not depend upon θ and that Y1 is a sufficient statistics for θ.

The converse is proven by taking:

g(y_1,\dots,y_n;\theta)=g_1(y_1; \theta) h(y_2, \dots, y_n | y_1),\,

where h(y_2, \dots, y_n | y_1) does not depend upon θ because Y2...Yn depend only upon X1...Xn which are independent on Θ when conditioned by Y1, a sufficient statistics by hypothesis. Now divide both members by the absolute value of the non-vanishing Jacobian J, and replace y_1, \dots, y_n by the functions u_1(x_1, \dots, x_n), \dots, u_n(x_1,\dots, x_n) in x_1,\dots, x_n. This yields

\frac{g\left[ u_1(x_1, \dots, x_n), \dots, u_n(x_1, \dots, x_n); \theta \right]}{|J*|}=g_1\left[u_1(x_1,\dots,x_n); \theta\right] \frac{h(u_2, \dots, u_n | u_1)}{|J*|}

where J * is the Jacobian with y_1,\dots,y_n replaced by their value in terms x_1, \dots, x_n. The left-hand member is necessarily the joint pdf f(x_1;\theta)\cdots f(x_n;\theta) of X_1,\dots,X_n. Since h(y_2,\dots,y_n|y_1), and thus h(u_2,\dots,u_n|u_1), does not depend upon θ, then

H(x_1,\dots,x_2)=\frac{h(u_2,\dots,u_n|u_1)}{|J*|}

is a function that does not depend upon θ.

We use the shorthand notation to denote the joint probability of (X,T(X)) by fθ(x,t). Since T is a function of X, we have fθ(x,t) = fθ(x) and thus:

fθ(x) = fθ(x,t) = fθ | t(x)fθ(t)

with the last equality being true by the definition of conditional probability distributions. Thus fθ(x) = a(x)bθ(t) with a(x) = fθ | t(x) and b(x) = fθ(t).

Reciprocally, if fθ(x) = a(x)bθ(t), we have


\begin{align}
f_\theta(t) & = \sum _{x : T(x) = t} f_\theta(x, t) \\ 
& = \sum _{x : T(x) = t} f_\theta(x) \\
& = \sum _{x : T(x) = t} a(x) b_\theta(t) \\
& = \left( \sum _{x : T(x) = t} a(x) \right) b_\theta(t).
\end{align}

With the first equality by the definition of pdf for multiple variables, the second by the remark above, the third by hypothesis, and the fourth because the summation is not over t.

Thus, the conditional probability distribution is:


\begin{align}
f_{\theta|t}(x)
& = \frac{f_\theta(x, t)}{f_\theta(t)} \\
& = \frac{f_\theta(x)}{f_\theta(t)} \\
& = \frac{a(x) b_\theta(t)}{\left( \sum _{x : T(x) = t} a(x) \right) b_\theta(t)} \\
& = \frac{a(x)}{\sum _{x : T(x) = t} a(x)}.
\end{align}

With the first equality by definition of conditional probability density, the second by the remark above, the third by the equality proven above, and the fourth by simplification. This expression does not depend on θ and thus T is a sufficient statistic.[4]

Minimal sufficiency

A sufficient statistic is minimal sufficient if it can be represented as a function of any other sufficient statistic. In other words, S(X) is minimal sufficient if and only if

  1. S(X) is sufficient, and
  2. if T(X) is sufficient, then there exists a function f such that S(X) = f(T(X)).

Intuitively, a minimal sufficient statistic most efficiently captures all possible information about the parameter θ.

A useful characterization of minimal sufficiency is that when the density fθ exists, S(X) is minimal sufficient if and only if

\frac{f_\theta(x)}{f_\theta(y)} is independent of θ :\Longleftrightarrow S(x) = S(y)

This follows as a direct consequence from Fisher's factorization theorem stated above.

A case in which there is no minimal sufficient statistic was shown by Bahadur, 1957[5] . However, under mild conditions, a minimal sufficient statistic does always exist. In particular, in Euclidean space, these conditions always hold if the random variables (associated with Pθ ) are all discrete or are all continuous.

If there exists a minimal sufficient statistic, and this is usually the case, then every complete sufficient statistic is necessarily minimal sufficient[6](note that this statement does not exclude the option of a pathological case in which a complete sufficient exists while there is no minimal sufficient statistic). While it is hard to find cases in which a minimal sufficient statistic does not exist, it is not so hard to find cases in which there is no complete statistic.

The collection of likelihood ratios \left\{\frac{L(\theta_1|X)}{L(\theta_2|X)}\right\} is a minimal sufficient statistic if P(X | θ) is discrete or has a density function.

Examples

Bernoulli distribution

If X1, ...., Xn are independent Bernoulli-distributed random variables with expected value p, then the sum T(X) = X1 + ... + Xn is a sufficient statistic for p (here 'success' corresponds to Xi = 1 and 'failure' to Xi = 0; so T is the total number of successes)

This is seen by considering the joint probability distribution:

 \Pr\{X=x\}=\Pr\{X_1=x_1,X_2=x_2,\ldots,X_n=x_n\}.

Because the observations are independent, this can be written as


p^{x_1}(1-p)^{1-x_1} p^{x_2}(1-p)^{1-x_2}\cdots p^{x_n}(1-p)^{1-x_n} \,\!

and, collecting powers of p and 1 − p, gives


p^{\sum x_i}(1-p)^{n-\sum x_i}=p^{T(x)}(1-p)^{n-T(x)} \,\!

which satisfies the factorization criterion, with h(x)=1 being just a constant.

Note the crucial feature: the unknown parameter p interacts with the data x only via the statistic T(x) = Σ xi.

Uniform distribution

If X1, ...., Xn are independent and uniformly distributed on the interval [0,θ] (either a discrete or continuous interval), then T(X) = max(X1, ...., Xn ) is sufficient for θ – the sample maximum is a sufficient statistic for the population maximum.

To see this, consider the joint probability distribution:


\Pr(X=x)=P(X_1=x_1,X_2=x_2,\ldots,X_n=x_n).

Because the observations are independent, this can be written as


\frac{\operatorname{H}(\theta-x_1)}{\theta}\cdot
\frac{\operatorname{H}(\theta-x_2)}{\theta}\cdot\,\cdots\,\cdot
\frac{\operatorname{H}(\theta-x_n)}{\theta} \,\!

where H(x) is the Heaviside step function. This may be written as


\frac{\operatorname{H}\left(\theta-\max_i \{\,x_i\,\}\right)}{\theta^n}\,\!

which can be viewed as a function of only θ and maxi(Xi) = T(X). This shows that the factorization criterion is satisfied, again where h(x)=1 is constant (Is this correct?). Note that the parameter θ interacts with the data only through the data's maximum.

In fact, the minimum-variance unbiased estimator (MVUE) for θ is

\frac{n+1}{n}T(X) - 1

This is the sample maximum, scaled and shifted to correct the bias, and is MVUE by the Lehmann–Scheffé theorem. Further, the sample maximum is also the maximum likelihood estimator for the population maximum.

Poisson distribution

If X1, ...., Xn are independent and have a Poisson distribution with parameter λ, then the sum T(X) = X1 + ... + Xn is a sufficient statistic for λ.

To see this, consider the joint probability distribution:


\Pr(X=x)=P(X_1=x_1,X_2=x_2,\ldots,X_n=x_n).

Because the observations are independent, this can be written as


{e^{-\lambda} \lambda^{x_1} \over x_1 !} \cdot 
{e^{-\lambda} \lambda^{x_2} \over x_2 !} \cdot\,\cdots\,\cdot 
{e^{-\lambda} \lambda^{x_n} \over x_n !} \,\!

which may be written as


e^{-n\lambda} \lambda^{(x_1+x_2+\cdots+x_n)} \cdot 
{1 \over x_1 ! x_2 !\cdots x_n ! } \,\!

which shows that the factorization criterion is satisfied, where h(x) is the reciprocal of the product of the factorials. Note the parameter λ interacts with the data only through its sum T(X).

Rao–Blackwell theorem

Sufficiency finds a useful application in the Rao–Blackwell theorem. It states that if g(X) is any kind of estimator of θ, then typically the conditional expectation of g(X) given T(X) is a better estimator of θ, and is never worse. Sometimes one can very easily construct a very crude estimator g(X), and then evaluate that conditional expected value to get an estimator that is in various senses optimal.

Exponential family

According to the Pitman-Koopman-Darmois theorem, among families of probability distributions whose domain does not vary with the parameter being estimated, only in exponential families is there a sufficient statistic whose dimension remains bounded as sample size increases. Less tersely, suppose X_n, n = 1, 2, 3, \dots are independent identically distributed random variables whose distribution is known to be in some family of probability distributions. Only if that family is an exponential family is there a (possibly vector-valued) sufficient statistic T(X_1, \dots, X_n) whose number of scalar components does not increase as the sample size n increases.

This theorem shows that sufficiency (or rather, the existence of a scalar or vector-valued of bounded dimension sufficient statistic) sharply restricts the possible forms of the distribution.

See also

Notes

  1. ^ Fisher, R.A. (1922). "On the mathematical foundations of theoretical statistics". Philosophical Transactions of the Royal Society of London. Series A 222: 309-368. doi:10.1098/rsta.1922.0009. JSTOR: 91208. JFM 48.1280.02. http://digital.library.adelaide.edu.au/dspace/handle/2440/15172. 
  2. ^ Stigler, Stephen (December 1973). "Studies in the History of Probability and Statistics. XXXII: Laplace, Fisher and the Discovery of the Concept of Sufficiency". Biometrika 60 (3): 439–445. doi:10.1093/biomet/60.3.439. MR0326872, JSTOR: 2334992. 
  3. ^ Casella, George; Berger, Roger L. (2002). Statistical Inference, 2nd ed. Duxbury Press. 
  4. ^ "The Fisher–Neyman Factorization Theorem". http://cnx.org/content/m11480/1.6/. 
  5. ^ Lehmann and Casella
  6. ^ Lehmann and Casella , page 72

References


 
 

 

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