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| Britannica Concise Encyclopedia: thermal radiation |
For more information on thermal radiation, visit Britannica.com.
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| US Military Dictionary: thermal radiation |
1. the heat and light produced by a nuclear explosion.
2. electromagnetic radiation emitted from a heat or light source as a consequence of its temperature. It consists essentially of ultraviolet, visible, and infrared radiations.
See the Introduction, Abbreviations and Pronunciation for further details.
| Architecture: thermal radiation |
The transmission of heat from a hot surface to a cooler one in the form of invisible electromagnetic waves, which, on being absorbed by the cooler surface, raise the temperature of that surface without warming the space between.
| Military Dictionary: thermal radiation |
(DOD, NATO) 1. The heat and light produced by a nuclear explosion. 2. (DOD only) Electromagnetic radiations emitted from a heat or light source as a consequence of its temperature; it consists essentially of ultraviolet, visible, and infrared radiations.
| Wikipedia: Thermal radiation |
Thermal radiation is electromagnetic radiation emitted from the surface of an object which is due to the object's temperature. An example of thermal radiation is the infrared radiation emitted by a common household radiator or electric heater. A person near a raging bonfire will feel the radiated heat of the fire, even if the surrounding air is very cold. Thermal radiation is generated when heat from the movement of charged particles within atoms is converted to electromagnetic radiation. Solar radiation heats the earth during the day, while at night the earth re-radiates some heat back into space.
If the object is a black body in thermodynamic equilibrium, the radiation is termed black-body radiation[1]. The emitted wave frequency of the black body thermal radiation is described by a probability distribution depending only on temperature, and for a genuine black body in thermodynamic equilibrium is given by Planck’s law of radiation. Wien's law gives the most likely frequency of the emitted radiation, and the Stefan–Boltzmann law gives the radiant intensity.[2]
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There are four main properties that characterize thermal radiation:
These properties apply if the distances considered are much larger than the wavelengths contributing to the spectrum (around 10 micrometres at 300 K). Indeed, thermal radiation here takes only travelling waves into account. A more sophisticated framework involving electromagnetics has to be used for lower distances (near-field thermal radiation).
| °C | Subjective colour |
|---|---|
| 480 | faint red glow |
| 580 | dark red |
| 730 | bright red, slightly orange |
| 930 | bright orange |
| 1100 | pale yellowish orange |
| 1300 | yellowish white |
| > 1400 | white (yellowish if seen from a distance) |
Thermal radiation is an important concept in thermodynamics as it is partially responsible for heat exchange between objects, as warmer bodies radiate more heat than colder ones. (Other factors are convection and conduction.) The interplay of energy exchange is characterized by the following equation:

Here,
represents spectral absorption factor,
spectral reflection factor and
spectral transmission factor. All these elements depend also on the wavelength
. The spectral absorption factor is equal to the emissivity
; this relation is known as Kirchhoff's law of thermal radiation. An object is called a black body if, for all frequencies, the following formula applies:

In a practical situation and room-temperature setting, humans lose considerable energy due to thermal radiation. However, the energy lost by emitting infrared heat is partially regained by absorbing the heat of surrounding objects (the remainder resulting from generated heat through metabolism). Human skin has an emissivity of very close to 1.0 .[3] Using the formulas below then shows a human being, roughly 2 square meter in area, and about 307 kelvins in temperature, continuously radiates about 1000 watts. However, if people are indoors, surrounded by surfaces at 296 K, they receive back about 900 watts from the wall, ceiling, and other surroundings, so the net loss is only about 100 watts. These heat transfer estimates are highly dependent on extrinsic variables, such as wearing clothes (decreasing total thermal "circuit" conductivity, therefore reducing total output heat flux.) Only truly "grey" systems (relative equivalent emissivity/absorptivity and no directional transmissivity dependence in all control volume bodies considered.) can achieve reasonable irradiative flux estimates through the Stefan-Boltzmann law. However, encountering this "ideally calculable" situation is virtually impossible (although common engineering procedures surrender the dependency of these unknown variables and "assume" this to be the case). Optimistically, these "grey" approximations will get you close to real solutions, as most divergence from Stefan-Boltzmann solutions is small (especially in most lab controlled environments).
If objects appear white (reflective in the visual spectrum), they are not necessarily equally reflective (and thus non-emissive) in the thermal infrared; e. g. most household radiators are painted white despite the fact that they have to be good thermal radiators. Acrylic and urethane based white paints have 93% blackbody radiation efficiency at room temperature[citation needed] (meaning the term "black body" does not always correspond to the visually perceived color of an object). These materials that do not follow the "black color = high emissivity/absorptivity" caveat will most likely have functional spectral emissivity/absorptivity dependence.
Calculation of radiative heat transfer between groups of object, including a 'cavity' or 'surroundings' requires solution of a set of simultaneous equations using the Radiosity method. In these calculations, the geometrical configuration of the problem is distilled to a set of numbers called view factors, which give the proportion of radiation leaving any given surface that hits another specific surface. These calculations are important in the fields of solar thermal energy, boiler and furnace design and raytraced computer graphics.
Thermal radiation power of a black body per unit of area, unit of solid angle and unit of frequency ν is given by Planck's law as:

or

where β is a constant.
This formula mathematically follows from calculation of spectral distribution of energy in quantized electromagnetic field which is in complete thermal equilibrium with the radiating object.
Integrating the above equation over ν the power output given by the Stefan–Boltzmann law is obtained, as:

where the constant of proportionality σ is the Stefan–Boltzmann constant and A is the radiating surface area.
Further, the wavelength
, for which the emission intensity is highest, is given by Wien's Law as:

For surfaces which are not black bodies, one has to consider the (generally frequency dependent) emissivity factor ε(υ). This factor has to be multiplied with the radiation spectrum formula before integration. If it is taken as a constant, the resulting formula for the power output can be written in a way that contains ε as a factor:

This type of theoretical model, with frequency-independent emissivity lower than that of a perfect black body, is often known as a gray body. For frequency-dependent emissivity, the solution for the integrated power depends on the functional form of the dependence, though in general there is no simple expression for it. Practically speaking, if the emissivity of the body is roughly constant around the peak emission wavelength, the gray body model tends to work fairly well since the weight of the curve around the peak emission tends to dominate the integral.
Definitions of constants used in the above equations:
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Planck's constant | 6.626 0693(11)×10−34 J·s = 4.135 667 43(35)×10−15 eV·s |
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Wien's displacement constant | 2.897 7685(51)×10−3 m·K |
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Boltzmann constant | 1.380 6505(24)×10−23 J·K−1 = 8.617 343(15)×10−5 eV·K−1 |
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Stefan–Boltzmann constant | 5.670 400(40)×10−8 W·m−2·K−4 |
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Speed of light | 299,792,458 m·s−1 |
Definitions of variables, with example values:
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Temperature | Average surface temperature on Earth = 288 K |
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Surface area | Acuboid = 2ab + 2bc + 2ac; Acylinder = 2π·r(h + r); Asphere = 4π·r2 |
| This article includes a list of references, related reading or external links, but its sources remain unclear because it lacks inline citations. Please improve this article by introducing more precise citations where appropriate. (October 2007) |
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