$arr=array(2,5,4,6,7,8,1);

for($i=0;$i<count($arr);$i++)

{

for($j=$i;$j<count($arr);$j++)

{

if($arr[$i] > $arr[$j])

{

$temp=$arr[$i];

$arr[$i]=$arr[$j];

$arr[$j]=$temp;

}

}

}

No arr refers to address of array &arr refers address of address of array but compiler treats arr and & arr, so even you place arr and & arr no error only warnings will be displayed.

Yes, 'ARR' and 'ARR' are the same for char20. Whatever it means.

There is no such person as Trad Long.

for example:

int arr[3];

arr[0] = 1; /* ok */
arr[1] = 2; /* ok */
arr[2] = 0; /* ok */
arr[3] = -1; /* wrong */
arr[-1] = -3; /* wrong */