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Do you mean: u² + 2u + 1 - v²? If so then

= (u + 1)2 - v2

= [(u + 1) + v][(u + 1) - v]

= (u + 1 + v)(u + 1 - v)

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Related answers

Do you mean: u² + 2u + 1 - v²? If so then

= (u + 1)2 - v2

= [(u + 1) + v][(u + 1) - v]

= (u + 1 + v)(u + 1 - v)

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-1

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v = -1

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D=E/((1+v)(1-2v))*[1-v v v 0 0 0; v 1-v v 0 0 0; v v 1-v 0 0 0; 0 0 0 0.5(1-2v) 0 0; 0 0 0 0 0.5(1-2v); 0 0 0 0 0 0.5(1-2v)]

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1/f = 1/u+1/v

Subtract 1/v from both sides:

1/f-1/v = 1/u

Multiply all terms by fv:

fv/f - fv/v = fv/u => v-f = fv/u

Multiply all terms by u:

u(v-f) = fv

Divide both sides by v-f which will then make u the subject of the formula:

u = fv/v-f

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