0
Do you mean: u² + 2u + 1 - v²? If so then
= (u + 1)2 - v2
= [(u + 1) + v][(u + 1) - v]
= (u + 1 + v)(u + 1 - v)
-1
v = -1
D=E/((1+v)(1-2v))*[1-v v v 0 0 0; v 1-v v 0 0 0; v v 1-v 0 0 0; 0 0 0 0.5(1-2v) 0 0; 0 0 0 0 0.5(1-2v); 0 0 0 0 0 0.5(1-2v)]
1/f = 1/u+1/v
Subtract 1/v from both sides:
1/f-1/v = 1/u
Multiply all terms by fv:
fv/f - fv/v = fv/u => v-f = fv/u
Multiply all terms by u:
u(v-f) = fv
Divide both sides by v-f which will then make u the subject of the formula:
u = fv/v-f