Sorry, I accidentally sent this Q up without finishing it.
(3y2 - 3y)/(y - 1) = 3y(y - 1)/(y - 1) = 3y
-3y + y = -2y
-8
3y2 y x y = y2 3 x y2 = 3y2
if you wish to multiply 3y-2y by 3y-y the answer is 2y^2
y2-3y=0 y(y-3) y=0,3
5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7
3xy + 3y2 = 3y (x + y)
OK, so-3y + 15 - y = 39-3y + 15 - 15 - y = 39 - 15-3y -y = 24-4y = 24-y = 6y= -6.Hope this helps!
(3y + 5)(y - 2)
4xy²(3y-x)-2x²(x-3y)²=4xy²(x-3y)-2x²(x-3y)²=(x-3y)[4xy²-2x²(x-3y)²]=(x-3y)(4xy²-2x³+6x²y)=(x-3y)(-2x³+6x²y+4xy²)=-2x(x-3y)(x²-3xy-2y²)= -2x(x-3y)(x-y)(x-2y)
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x