volume = pi r squared multiplied by the length you didnt specify wether 2 inch pipe was diameter or radius
To find the volume of liquid that will fill a 1000 ft length of a 3.4 inch pipe, first calculate the cross-sectional area of the pipe using the formula for the area of a circle, (A = \pi r^2). The radius (r) is half of the diameter; for a 3.4 inch pipe, the radius is 1.7 inches, or 0.1417 feet. The volume (V) can be calculated as (V = A \times L), where (L) is the length of the pipe (1000 ft). This results in a volume of approximately 60.23 cubic feet, which is equivalent to about 449.2 gallons.
If the flow velocity remains the same the flow volume will increase by the square of the diameter ratio.(2/1.25) = 1.6 = diameter ratio1.62 = 2.56 more flow volume through 2 inch pipe compared to 1.25 inch pipe.
Volume of the pipe = 4.896 gallons
To find the volume of a pipe, you can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height of the cylinder. For a 2-inch diameter pipe, the radius is 1 inch. Thus, the volume of 12 inches of 2-inch pipe would be π * 1^2 * 12 = 12π cubic inches.
To calculate the volume of gas in a 1000-foot length of 8-inch diameter pipe at 500 PSI, we first determine the internal volume of the pipe. The internal volume can be calculated using the formula for the volume of a cylinder: ( V = \pi r^2 h ). For an 8-inch diameter pipe, the radius is 4 inches (or 0.333 feet), and with a height of 1000 feet, the internal volume is approximately 3,141.59 cubic feet. At 500 PSI, the volume of gas would be compressed, so the actual amount of gas would depend on the specific gas properties and conditions, which would require additional calculations using the ideal gas law or other relevant equations.
Assuming that 0.75 inch refers to the diameter, the volume is pi*(0.75/2)2*12 = 5.3 cubic inches, approx.
The volume of a cylinder (pipe) is: pi*(r^2)h If a pipe has an 8 inch radius, then to find the volume you substitute: V = pi*(8^2)h If a pipe has a 4 inch radius, then to find the volume you substitue: V = pi*(4^2)h Thus, an eight inch pipe can carry 150.72*h more units cubed.
To determine how much water a 6-inch pipe can hold, you need to calculate its volume based on its length. The volume (in gallons) can be found using the formula for the volume of a cylinder: ( V = \pi r^2 h ), where ( r ) is the radius (3 inches for a 6-inch pipe) and ( h ) is the length of the pipe in inches. For example, a 10-foot (120-inch) length of a 6-inch pipe would hold about 18.9 gallons of water.
It is based on the flow area, which is proportional to the square of the diameter. 2 squared = 4. 4 squared = 16. So, the 4 inch pipe can take 16/4 = 4 times the volume of the 2 inch pipe. It might be less confusing if you had picked sizes other than 2 and 4. This is a rough calculation, since pipe inside diameters are not the same as nominal sizes, but close enough for most purposes.
You would need to know the length of the pipe in order to answer the question. The equation for volume of a cylinder is V=πr2h. For example, for one foot of 2" pipe, you would multiply 3.14 by 2" by 12" and find you have 37.7 cubic inches of volume inside the pipe.
The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.
Yes, a single 4-inch pipe can carry more volume than two 2-inch pipes. The cross-sectional area of a 4-inch pipe is significantly larger, allowing it to transport more fluid. Specifically, the area of a 4-inch pipe is approximately 12.57 square inches, while the combined area of two 2-inch pipes is about 6.28 square inches. Therefore, the 4-inch pipe will have a higher flow capacity.