At the moment of release, all the energy stored in the bow (100J) is converted to the kinetic energy of the arrow. So, the kinetic energy of the arrow at that moment is 100J.
The efficiency of the motor can be calculated by dividing the useful energy output by the total energy input and multiplying by 100. In this case, the efficiency would be 70J (useful energy output) divided by 100J (total energy input) = 0.7 or 70%.
Eff = Output/Input.
The efficiency of the boiler is calculated as the ratio of useful energy output (100J) to the total energy input (111J), which is then multiplied by 100 to get the percentage. So, efficiency = (100/111) * 100 = 90.09%.
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. Therefore, if you do 100 J of work on a cart with no friction, its kinetic energy will increase by the same amount, resulting in a total kinetic energy increase of 100 J.
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a lot.
The gravitational potential energy of a 2kg object 1m off the ground is 2kg × g × 1m = 19.6J, where g is the acceleration at 9.8m/sec2.
The efficiency of the motor can be calculated as the ratio of useful output energy to input energy. In this case, the efficiency would be 70J (useful kinetic energy) divided by 100J (electrical energy) multiplied by 100% to get a percentage. So, the efficiency of the motor is 70%.
yes it can
A force of 10 newtons acting through a distance of 10 meters does 100 joules of work. Power is defined as the rate at which that work is done. So the power during the push is (100) divided by (the number of seconds the push lasts). Doing the job in less time indicates more power, just as you'd expect. But the total energy delivered is still 100 joules, regardless of how slowly or quickly it's delivered.
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