(B^-1)B = 1 B^(-1xB) = 1/(B^B)
b*1/b=1
-1, because if you factor out -1 from a-b you get -1(-a+b). when you reduce, -a+b = b-a so those cancel out and you are left with -1
b+b+b+b+b is equal to 5b. That is because there are five b's being added up. 1+1+1+1+1 is 5 because there are five 1's being added up.
By definition (-1)*(-1)=1.(-a)*(-b)(-1)*(a)*(-1)*(b)(-1)*(-1)*(a)*(b)(a)*(b) ■
9 and 10 First the main formulas: a+b=19 a-b=1 Find out what one of the variables are. We can choose "a" or "b" from either of the two formulas. Let's choose "a" from the a-b=1 formula. a - b = 1 [formula] a-b (+b) = 1 (+b) [solve for "a" by removing "b"] a = 1+b Plug that "a" into the other formula a+b=19. a + b = 19 (1+b) +b = 19 1 + 2b = 19 1 + 2b - 1 = 19 -1 2b = 18 b = 9 Plug that into our formula solved from before for "a" a = 1 + b a = 1 + (9) a = 10
one a/b X b/a = a/a X b/b =1/1 = 1
If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
Oh, dude, B to the power of -1 is just 1 divided by B. It's like flipping B upside down and giving it a little math makeover. So yeah, B to the power of -1 equals 1/B. Math can be pretty chill sometimes, you know?
Multiplicative identitya*1 = aReciprocalitya * b = 1then a and b are reciprocals: a = 1/b and b = 1/aAssociativitya * (b * c) = (a * b) * cCommutativitya * b = b * aDistributivitya * (b + c) = a*b + a*c
b(b^2 + 1)(b^4 - b^2 + 1)
8b^2 -9b +1 8b^2 -8b -b +1 8b(b-1) - 1(b-1) (8b-1)(b-1)