One bird in the hand is worth two in the bush.
-1
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
A bird in the hand equals two in the bush.
A = 36 mi2, h = 12 mi, b = ? mi A = (bh)/2, multiply by 2 to both sides 2A = bh, divide by h to both sides (2A)/h = b, substitute A and h respectively with 36 and 12 (2*36 mi2)/(12 mi) = b, simplify b = 6 mi
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
Factor 2h−2 2h−2 =2(h−1) Answer: 2(h−1)
The equation for the area of a triangle is A=1/2 (b*h). So your equation would A= 1/2 (3.8*2.5), which equals 4.75
0.5*B*H = 36 square miles
(2h-3)(h+1) = 0 h = 3/2 or h = -1
A=1/2(b1+b2)h A=1/2(7+12)5 A=1/2(19)5 A=9.5x5 A=47.5
The area of a trapezoid is equal to (1/2)(B + b)h]. In our case B = 10 ft, b = 8 ft, and h = 5 ft, So A = (1/2)(B + b)h = (1/2)(10 + 8)(5) = 45 ft^2
A=area b=base h=height A=1/2*b*h