1 mole is itself, a quantity. But, if you like, the quantity is 6.022140857*10^23 atoms of fluorine.
The answer depends on the quantity of XeF6
If the quantity of 1 mole of carbon is 12, then the quantity of 1 mole of lithium would be its molar mass, which is approximately 6.94 g. The mole concept relates the amount of substance, so 1 mole of any element will contain Avogadro's number (6.022 x 10^23) of atoms or molecules.
1 mol of fluorine atoms (F) is 18,998 403 163(6) g.
Avogadro first named the mole, and it is 6.02x10^23 atoms=1 mole
25.9 grams fluorine (1 mole F/19.0 grams)(6.022 X 1023/1 mole F) = 8.21 X 1023 atoms of fluorine ======================
One mole of freon CCl2F2 contains 1 atom of carbon, 2 atoms of chloride, and 2 atoms of fluorine. The chemical ratio of carbon to chloride to fluorine in freon CCl2F2 is 1:2:2.
The cost of fluorine can vary depending on the supplier and quantity purchased. As of now, the price of fluorine is approximately $0.07 per gram.
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
In 1 mole of CF₄, there are 4 moles of fluorine atoms since each molecule of CF₄ contains 4 fluorine atoms. Therefore, in 1.8 moles of CF₄, the number of moles of fluorine atoms is 1.8 moles × 4 = 7.2 moles of fluorine. To find the total number of fluorine atoms, multiply 7.2 moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mole), resulting in about (4.34 \times 10^{24}) fluorine atoms.
The heat of fusion of fluorine is approximately 2.62 kJ/mol. This value represents the amount of energy required to convert 1 mole of solid fluorine into liquid fluorine at its melting point while keeping the temperature constant.
False
The answer depends on the quantity of Xenon.