1 mole is itself, a quantity. But, if you like, the quantity is 6.022140857*10^23 atoms of fluorine.
25.9 grams fluorine (1 mole F/19.0 grams)(6.022 X 1023/1 mole F) = 8.21 X 1023 atoms of fluorine ======================
There is 19g of fluorine. That makes 1 mole.
it can be said that 1 mole oflithium is equal in mass to its molar mass wwhich is 6.94 g/mol
1 mol of fluorine atoms (F) is 18,998 403 163(6) g.
The answer is two moles of F atoms or 1 mole of F2 molecules.
Avogadro first named the mole, and it is 6.02x10^23 atoms=1 mole
5.88 mg ClF3 (1 gram/1000 mg)(1 mole ClF3/92.45 g)(3 mole F/1 mole ClF3)(6.022 X 10^23/1 mole F) = 1.15 X 10^20 atoms of fluorine
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
False
its False
2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
1 mole