our point A(x,y) becomes A'(-x,-y).
The earth is tilted about 23 degrees 26 minutes. Or, 23 1/2 degrees on its axis. The earth rotates west to east, and if you look down at the earth from the North pole, it will be rotating counter clockwise. if you look up at the earth from the south pole, then the earth will be rotating clockwise.
It is an angle whose measure is 46/360 = 23/180 of a full rotation.
The same way as earth.If viewed from above the Sun's north pole, all of the planets orbiting the sun do so in a counter-clockwise direction. All the planets except Venus also rotate counter-clockwise.
It is: 157+23 = 180
337
If regular, use the formula: ((n-2)180)/n. ((23-2)180)/23 ((21)180)/23 3780/23 There is approximately 164.347826086956521...° in each internal angle of a icosikaitrigon.
I think so.I am not an astrophysicist, but think about it. Given the concept it seems that the length of the day would have to change. My long-winded explanation for visual/kinetic learners follows.Imagine a simplified diagram in which you have a marker set upright on a table and a ball being rotated while orbiting around it; a simulation of the Earth's rotation and orbit around the sun.Imagine that ball is orbiting counter-clockwise while rotating clockwise [Figure A]. Changing only rotational direction the ball is now orbiting counter-clockwise while also rotating counter-clockwise [Figure B].In [Figure B], holding rotation and orbital speed constant, the amount of time any given section of the ball's surface is continuously exposed to the marker in the center of the orbit is greater than in [Figure A].However, given the huge scale of the Earth's orbit around the sun, the difference may be negligible. Also, and I'm ignorant of the facts here, this 2-dimensional model assumes rotation and orbit are happening on a 2D plane. If, for instance the ball were to spin away from or towards the marker, then orbit would not affect the exposure time and all that would matter is rotation speed. And that's where astrophysicists come in.Another Answer, confirming the first answer:Viewed from a place above the north pole, the Earth is rotating about its axis in a counter-clockwise direction, with a sidereal rotation speed (speed relative to the distant stars) of 23 hour and 56 some odd minutes.At the same time, the Earth is revolving around the Sun in a counter-clockwise direction, with a revolution speed of about 365.25 some odd days.In the time it takes the Earth to rotate one sidereal day, it has also moved a little bit relative to the Sun, and its angle with respect to the Sun has changed. It takes an extra 3 some odd minutes for the Sun's apparent position to match the prior day's position. (Ignoring axial tilt, which does not matter for this explanation.) That 24 hours is one tropical day. It is actually an average time, because the length of the day varies as the Earth revolves around the Sun.With all else equal, except for the Earth to be rotating clockwise instead of counter-clockwise, the sidereal day would still be 23 hours and 56 some odd minutes, but the tropical day would be shortened to 23 hours and 52 some odd minutes, because the velocity of the angle of the sun would be faster.Since we base our time on the rotation speed of the Earth relative to the Sun, we would then have a different time standard, one that runs slightly faster, and we would probably still call the tropical day 24 hours, but the sidereal day would be around 24 hours 3 some odd minutes.
3,780 degrees Formula: 180(s-2) s=sides 180(23-2)=180*21=3,780
46/180 = 23/90
Adding 180 days to November 23, 2010 gives May 22, 2011.
23
7.8261