23.74cm3 0.0147 mol dm-3NaOHare required to neutralize 25.00 cm3 of HCl calculate concentration of HCl acid in moldm-3and g dm-3?

Answer 1

HCl + NaOH ― NaCl + H2O

nNaOH = c*v

= 0.01470 * 23.74*10-3L

= 3.49*10-4 mol

1 mol HCl reacts with 1 mol NaOH

therefore

nHCl = 3.49*10-4mol

CHCL= nNaOH /VNaOH

= 3.49*10-4 / 25.00*10-3

= 13.96 * 10-3 mol.dm-3

Answer 2

To calculate the concentration of HCl in mol/dm^3, first calculate the amount (in mol) of NaOH used in the reaction using the formula Molarity = moles/volume. Then use the balanced chemical equation to determine the amount (in mol) of HCl that reacted with the NaOH. Lastly, calculate the concentration of HCl in mol/dm^3 by dividing the moles of HCl by the volume. To convert the concentration from mol/dm^3 to g/dm^3, use the molar mass of HCl (36.46 g/mol) and the concentration in mol/dm^3 to find the concentration in g/dm^3.