2 Blanks (Blank Tiles) in a Scrabble Game
2 Balls in a Spare Game (in Ten Pin Bowling)
easy-g a g g g g a g g g a g a a (2 times)-b b g g a a b g bb g g a a g -g a g g g g a g g g a g a a (2 times) hard-g a b b c b a g b b a g a a g a b b c b a g b b a g g a g d d b b a b c a b c d d a b c a b
G,a,b,g,b/c,b,a f#,g,a/b,b,b,/a,g (2*) (chorus) e,e,/b,b,/c,b e,e,e/b,b/c,b e,e/b,b/c,b g,g/,e/,g,g (2*) g,g,e,g,g,e,g,g,d,e,b,d,e (2*) e,e,e,e,e,e,e b,b,g,g,
E g e g e e g a b a g a / e g e g e e g a b a g a / e g e g e e g a b a g a e a b a / b a g / g g f f /f g a g g / b a g / g g f f / g a b g g g a b c2 / b b b g b g b b g b b b / g b g b b g / b b b g b g b g /c2 a g g g /c2 a g g g ................
d, e, d, g, g, a, b, a, d', b, a, b, e, e,d. you do that 2 times. then it is: b, g, b, b, a, e, a, a, g, e, g, g, g, g, e. you do that 2 times there is a high part to which is d',c',b,b,b,b c' d' c' a g you finished!!!
The B. G. was born on September 3, 1980.
b b aga X3 b(234)b b aga X3 g(234) g g g a g g g g a a b(2) b b b b agag b b agag the numbers are the beats you hold the note down. the notes that are put together (aga) for example,mean that you do it i 2 beats.
for regular keys it is (a a b b c c b a# a# a a g# g# g b b b a# A# a a g# g# g) that is most of it
A string; D (3) C# (2) B (1) rest (crochets) D (3) C# (2) B (1) rest (crochets) B (1) B (1) B (1) B (1) C# (2) C# (2) C# (2) C# (2) (quavers) D (3) C# (2) B (1) rest (crochets) D- note (2) - finger Music is set out in 4/4 time. 1 bar per line.
g g a b b a g a b g g g a b b a g a b g these are the first 2 lines up until out, im not sure about the others but i hope this helps
B B B B A G A B low C E G A G E G A G E G G G G G G G G G G G G G G G F G A G C E
Suppose there are B boys and G girls. Then Sophie has B brothers and (G-1) sisters - remember to leave Sophie out. So B = (G-1) + 5 ie B = G + 4 Also Joe has (B-1) brothers and G sisters So (B-1) = 2*G Substituting the value of B from Sophie's equation into this one gives (S+4 - 1) = 2*G ie G+3 = 2*G Subtract G from both sides: 3 = G and then B = G+4 = 7 So number of children in the family = B+G = 7+3 = 10.
Let's say that s is the total number of students, b is the number of boys, g is the total number of girls, n is the number of non-blonde girls, and e is the number if blonde girls. We know that s = b + g, b = g, g = n + e, e = g/3, and n = 10. Substituting for b in the first equation gives us s = g + g = 2g Then we substitute for n and e in the third equation and solve for g: g = g/3 + 10 g - g/3 = 10 g - (1/3)g = 10 (2/3)g = 10 g = 10 x (3/2) = 15 Finally, solve for s: s = 2g = 2 x 15 = 30