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Q: 30 equals J IN THE G N?

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Jumps in the Grand National

-1 is the G N I

three

G N J. Gilbert has written: 'Engineering data on malleable cast irons'

E E-G--J---N----S-----Y E (F) G (HI) J (KLM) N (OPQR) S (TUVWX) Y Thats how i figured it out ^^^

n = 3030 percent of n equals 930% * n = 930%/100% * n = 90.3n/0.3 = 9/0.3n = 30

4

E

N. G. J. van Schouwenburg has written: '\\' -- subject(s): Bible, Criticism, interpretation

#include<stdio.h> #include<conio.h> int G[50][50],n,i,j,h,k; void FGraph(); int findR(); void main() { clrscr(); printf("\t\t\tmultistage graph"); printf("\n enter the no of vertices:"); scanf("%d",&n); printf("\n there is a edge between the follwing vertices enter its weight else 0:\n"); for (i=1;i<=n;i++) for(j=1;j<=n;j++) { G[I][J]=0; IF(I!=J)&&(i<J)) { printf ("%d and%d:",i,j); scanf(%d,&G[i][j]); } } FGraph(); getch(); } void FGraph() { int cost[50],d[50],p[50],r; for(i=1;i<=n;i++) cost[i]=0; for(j=n-1;j>=1;j++) { r=findR(j+1); cost[j]=G[j][r]+cost[r]; d[j]=r; } p[1]=1;p[k]=n; for(j=2;j<k;j++) p[i]=d[p[j-1]]; printf("%d-",d[1]); for(j=2;j<n;j++) { if((d[j]==d[j-1])(d[j]==0)) continue; if(d[j]<=n) printf("%d-"d[j]); } printf("%d",n); } int findR(int cu) { int r1=n+1; for(h=1;h<=n;h++) {if((G[h][cu]!=0)&&(r1==n+1)){ r1=j; continue; } if(G[h][cu]!=0) { if(G[h][cu]<G[r1][cu]) r1=h; }} return r1; }sorry i have answerd in c++

N+18=30. Subtract 18 both sides N=12

It depends on the value of n.

123

Eyou count backwards.Y to S = 6S to N = 5N to J = 4J to G = 3then G to E = 2

450/15 = 30

1. n + 3*5 = 30 2. n + 15 = 30 3. n + 15 = 30 - 15 -15 n = 15

E

this is not correct F F F F F F F G A G F F F G F A N D A A J B E D J I N G

It is a linear equation in one variable, n.

if you put in what the problem equals then it can be answered

m-a-n-g-o i-n j-a-p-a-n-e-s-e

The answer is E

d

30 Days has September April June and November

30