30 = Jumps in the Grand National
30 Joules is equivalent to 0.03 gigajoules.
Jumps in the Grand National
-1 is the G N I
E E-G--J---N----S-----Y E (F) G (HI) J (KLM) N (OPQR) S (TUVWX) Y Thats how i figured it out ^^^
G N J. Gilbert has written: 'Engineering data on malleable cast irons'
three
n = 3030 percent of n equals 930% * n = 930%/100% * n = 90.3n/0.3 = 9/0.3n = 30
N. G. J. van Schouwenburg has written: '\\' -- subject(s): Bible, Criticism, interpretation
#include<stdio.h> #include<conio.h> int G[50][50],n,i,j,h,k; void FGraph(); int findR(); void main() { clrscr(); printf("\t\t\tmultistage graph"); printf("\n enter the no of vertices:"); scanf("%d",&n); printf("\n there is a edge between the follwing vertices enter its weight else 0:\n"); for (i=1;i<=n;i++) for(j=1;j<=n;j++) { G[I][J]=0; IF(I!=J)&&(i<J)) { printf ("%d and%d:",i,j); scanf(%d,&G[i][j]); } } FGraph(); getch(); } void FGraph() { int cost[50],d[50],p[50],r; for(i=1;i<=n;i++) cost[i]=0; for(j=n-1;j>=1;j++) { r=findR(j+1); cost[j]=G[j][r]+cost[r]; d[j]=r; } p[1]=1;p[k]=n; for(j=2;j<k;j++) p[i]=d[p[j-1]]; printf("%d-",d[1]); for(j=2;j<n;j++) { if((d[j]==d[j-1])(d[j]==0)) continue; if(d[j]<=n) printf("%d-"d[j]); } printf("%d",n); } int findR(int cu) { int r1=n+1; for(h=1;h<=n;h++) {if((G[h][cu]!=0)&&(r1==n+1)){ r1=j; continue; } if(G[h][cu]!=0) { if(G[h][cu]<G[r1][cu]) r1=h; }} return r1; }sorry i have answerd in c++
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4
N+18=30. Subtract 18 both sides N=12