3 pigs caught by the wolf.
W. P. C. Davies was born in 1928.
C. W. P. Moffatt has written: 'Science German course'
h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = H k Q 7 _ o W q K p c
1 (an) Ounce of Prevention is Worth a Pound of Cure.
it has three cases 1st E1- two balls are whiteE2- three balls are whiteE4-four balls are whiteE4/w= (p(E3)*4C2/4C2)/(P(E1)*2C2/4C2+P(E2)3C2/4C2+P(E3)*4C2/4C2)WHERE-P(E1)=P(E2)=P(E3)=1/3----------------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white
well the formula is p=2(l+w) p stands for perimeter l stands for length w stands for width P= l+l+w+w =5+5+3+3 = 16
Number 1 1st Branch: P(G) 1/3 P(W) 2/3 2nd Branch P(G) 1/5 P(W) 4/5 Total Probability P(G) 1/15 P(W) 4/15
white pieces on a chess board
5040 columns in a word processor
3, 61 and 113 are prime; the rest composite.
it's a puzzle! it goes o... f... p... of w... on c.s, and the ... are the rest of the word. this person wants to know the answer, but so do i. i have homework on it, so if you want to add please do! hope this "hint" helped!! :) :0 :P :D <3 8o ;D
the odds theoretically are almost infinity to 1 as they could be any color. -------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white