3x+12=x+48: 3x-x=-12+48
2x=36
x=18
3x + 12 = x + 48
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
x = 16 3x = 48 divide both sides by three to get x by itself x=16
The terms in x in the factorisation must be 3 and 1, the whole numbers must be factors of 48 ie 1/48, 2/24, 3/16, 4/12, or 6/8. The only ones which can combine with the 3 to give a sum of 24 are 4 and 12 viz: (3x + 12)(x + 4)
really depends. 12x - 8y = 48 3x - 2y = 12. You can't decide, but one ordered pair is (4,0)
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
x = 16 3x = 48 divide both sides by three to get x by itself x=16
The terms in x in the factorisation must be 3 and 1, the whole numbers must be factors of 48 ie 1/48, 2/24, 3/16, 4/12, or 6/8. The only ones which can combine with the 3 to give a sum of 24 are 4 and 12 viz: (3x + 12)(x + 4)
36 + 12 = 48
(3x-12)(x-4)
12 + 12 = 24. 24+12=32. 32 + 12 = 44
-3x + 4y = 12 Temporary value of y: 4y = 3x + 12 y = (3x + 12) / 4 Substituting y: -3x + 4 [(3x+12) / 4] = 12 -3x + 12x + 48 = 12 -3x + 12x = 12 - 48 9x = 12 - 48 9x = -36 x = -36 / 9 x = -4 Subtituting x to get the final value of y: -3(-4) + 4y = 12 12 + 4y = 12 4y = 12 - 12 4y = 0 y = 0 Final answer: x = -4 y = 0 Check: -3x + 4y = 12 -3(-4) + 4(0) = 12 12 + 0 = 12 12 = 12 Solution 2: -3x + 4y = 12 Temporay value of x: 3x = 4y - 12 x = (4y - 12) / 3 Substituting x to get the value of y: 3[(4y - 12) / 3] + 4y = 12 12y - 36 + 4y = 12 16y = 12 + 36 16y = 48 y = 48 / 16 y = 3 Substituting y to get the value of x: -3x + 4(3) = 12 -3x + 12 = 12 -3x = 12 - 12 x = 0 Final Answer: x = 0 y = 3 Check: -3(0) + 4(3) = 12 12 = 12
This is elementary stuff: 3x + 6 = 54 Subtract 6 from each side: 3x = 48 Divide each side by 3: x = 16.
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
many solutions
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