4 corners in a square
4 corners of a square.
4 Suits in a deck of cards.
4 squares in a point of cube
I guess 4 corners of a square. XD
s=(a+b+c)/2 inradius = √((s-a)(s-b)(s-c)/s) inradius for 3,4,5 = 1
MUSICAL 3 Vowels - U, I, A 4 Consonants - M, S, C, L
Cris
-2 for each S, +4 for C
An Energetic Member of the S-P-C-A- - 1912 was released on: USA: 4 December 1912
If you mean a circle inscribed in the square: C = circumference, π = pi, r = radius, s = side, P = perimeter C = 2πr r = s/2 C = πs s = P/4 C = πP/4 So for this problem, the circumference is 9π, or about 28.3 If you mean a square inscribed in the circle, the computations are practically the same, except: r = sqrt(2)s/2 C = sqrt(2)πs C = sqrt(2)πP/4 So for this problem, the circumference is sqrt(2)9π, or about 40.0
no....c,s&n