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52 C in P F J?

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Anonymous

16y ago
Updated: 8/17/2019

52 carti in pachetul de carti fara jokeri.

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16y ago

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#include<stdio.h> #include<conio.h> #include<string.h> void main() { char t[5],nt[10],p[5][5],first[5][5],temp; int i,j,not,nont,k=0,f=0; clrscr(); printf("\nEnter the no. of Non-terminals in the grammer:"); scanf("%d",&nont); printf("\nEnter the Non-terminals in the grammer:\n"); for(i=0;i<nont;i++) { scanf("\n%c",&nt[i]); } printf("\nEnter the no. of Terminals in the grammer: ( Enter e for absiline ) "); scanf("%d",&not); printf("\nEnter the Terminals in the grammer:\n"); for(i=0;i<nott[i]=='$';i++) { scanf("\n%c",&t[i]); } for(i=0;i<nont;i++) { p[i][0]=nt[i]; first[i][0]=nt[i]; } printf("\nEnter the productions :\n"); for(i=0;i<nont;i++) { scanf("%c",&temp); printf("\nEnter the production for %c ( End the production with '$' sign ) :",p[i][0]); for(j=0;p[i][j]!='$';) { j+=1; scanf("%c",&p[i][j]); } } for(i=0;i<nont;i++) { printf("\nThe production for %c -> ",p[i][0]); for(j=1;p[i][j]!='$';j++) { printf("%c",p[i][j]); } } for(i=0;i<nont;i++) { f=0; for(j=1;p[i][j]!='$';j++) { for(k=0;k<not;k++) { if(f==1) break; if(p[i][j]==t[k]) { first[i][j]=t[k]; first[i][j+1]='$'; f=1; break; } else if(p[i][j]==nt[k]) { first[i][j]=first[k][j]; if(first[i][j]=='e') continue; first[i][j+1]='$'; f=1; break; } } } } for(i=0;i<nont;i++) { printf("\n\nThe first of %c -> ",first[i][0]); for(j=1;first[i][j]!='$';j++) { printf("%c\t",first[i][j]); } } getch(); }


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P J F. Griffiths has written: 'Calculations in advanced Physical Chemistry'