5 + x + 5 = 25
Subtract 5 from each side:
x + 5 = 20
Do it again:
x = 15
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
(x + 5)(x + 5)
It is a linear equation in x. It has a solution, which is x = -5
4x + 5 + x = 25 5x + 5 = 25 Subtract 5 from both sides: 5x = 20 Divide both sides by 5: x = 4
x=5
5
No real solutions. But if you want to find the imaginaries: x=.5(25-i(337)^.5) y=.5(25-i(337)^.5) x^.5= the square root of x
If 40 plus x equals 25 then x is equal to -15.
x2 + 10 x + 25 = 2 (x+5)2 = 2 x+5 = +/- sqrt(2) x = -5 +/- sqrt(2)
-13 Plug 5 in and multiply it by -5 which equals -25 12 - 25 = -13
2x + 5 = 25 2x = 20x = 10
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5